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New answer posted
3 months agoContributor-Level 10
The maximum quantity of natural gas that can be transported that can be transported from M to Q is 6
New answer posted
3 months agoContributor-Level 10
From the figure and the conditions R can receive only 6 units (5 + 1) of natural gas if utilization is 100 Percent
New question posted
3 months agoNew answer posted
3 months agoContributor-Level 10
From the figure the maximum quantity of natural gas that S can receive = 6 + 2 + 9 = 17 units.
New answer posted
3 months agoContributor-Level 10
| Mohit | Manohar | Prashant | Dinesh |
Round – 4 | 3200 | 3200 | 3200 | 3200 |
Round – 3 | 1600 | 1600 | 1600 | 1600 |
Round – 2 | 800 | 800 | 7200 | 4000 |
Round – 1 | 400 | 6800 | 3600 | 2000 |
Initially | 6600 | 3400 | 1800 | 1000 |
New answer posted
3 months agoContributor-Level 10
| Mohit | Manohar | Prashant | Dinesh |
Round – 4 | 3200 | 3200 | 3200 | 3200 |
Round – 3 | 1600 | 1600 | 1600 | 1600 |
Round – 2 | 800 | 800 | 7200 | 4000 |
Round – 1 | 400 | 6800 | 3600 | 2000 |
Initially | 6600 | 3400 | 1800 | 1000 |
New answer posted
3 months agoContributor-Level 10
| Mohit | Manohar | Prashant | Dinesh |
Round – 4 | 3200 | 3200 | 3200 | 3200 |
Round – 3 | 1600 | 1600 | 1600 | 1600 |
Round – 2 | 800 | 800 | 7200 | 4000 |
Round – 1 | 400 | 6800 | 3600 | 2000 |
Initially | 6600 | 3400 | 1800 | 1000 |
New answer posted
3 months agoContributor-Level 10
| Mohit | Manohar | Prashant | Dinesh |
Round – 4 | 3200 | 3200 | 3200 | 3200 |
Round – 3 | 1600 | 1600 | 1600 | 1600 |
Round – 2 | 800 | 800 | 7200 | 4000 |
Round – 1 | 400 | 6800 | 3600 | 2000 |
Initially | 6600 | 3400 | 1800 | 1000 |
New answer posted
3 months agoContributor-Level 10
From the given condition g = 10,
Number of students who like both Physics and Maths = 10 + f
Number of students who like both chemistry and Maths = 10 + e
From given condition 10 + f = 10 + e or e = f
Similarly from 3rd condition ¾ (10 + e) = 10 + d
Or 30 + 3e = 40 + 4d
Or
d = 3e - 10/4
Since 15 students like only chemistry hence b = 15
Number of students who like only chemistry is 40
Hence e + g + d + b = 40
or e + 10 + (3e – 10)/4 + 15 = 40
or (7e – 10)/4 = 15 or 7e = 70 or e = 10
Hence a = 5, c = 20, f = e = 10, d = 5
Hence the distribution is as follows
As per the observation of class teacher actual numbers of students who lik
New answer posted
3 months agoContributor-Level 10
According to the information provided in the statement following arrangement will be obtained:
C | H | A | E | D | G | B | F |
1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 |
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