General Principles and Isolation of Elements

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alok kumar singh

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41. Option (i) and (iii)

Explanation: Haematite is an ore of iron that can be calcined and reduced by carbon. In the metallurgical process, calamine ore is calcined ore that can be reduced by carbon. Hence, option (i) and (ii) are correct.

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alok kumar singh

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40. Option (i) and (iii)

Calcination is the process of heating when the volatile matter escapes, leaving the metal oxide behind. It is usually done in the absence of air.

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39. Option (ii) and (iii)

The froth floatation method is most commonly used for sulfide ore. Sulfide ores galena (PbS) and copper pyrites  (CuFeS2) are found here.

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38. Option (iii) and (iv)

Bauxite consists of many impurities like hematite, goethite,  Fe2O3, the sand SiO2, etc.'

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alok kumar singh

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37. Option (ii) and (iii)

It is possible to separate two sulfide ores using the froth floatation process by adjusting the proportion of oil to water or by using 'depressants.' In the case of an ore containing ZnS and PbS, for example, the depressant used is NaCN.

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alok kumar singh

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36. Option (i) and (iii)

A suspension of powdered ore is made with water during the froth floatation process. Collectors and froth stabilizers are added to it. Collectors (e.g., pine oils, fatty acids, xanthates, etc.) improve the non wettability of the mineral particles, while froth stabilizers (e.g., cresols, aniline) keep the froth stable 

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35. Option (i) and (ii)

In the extraction of alumina by Hall-Heroult's process, alumina is mixed with cryolite with the mixture of fluorspar \& fluoride that increases the conductivity of electrical and lowers the melting point of Al2O3 .

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alok kumar singh

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34. Option (i) and (iv)

Pig iron is the iron obtained from the blast that has many impurities (Mn, P, Si, etc.) and approximately 4% carbon content. When it is re-melted or cast with the help of scrap iron, then it has less carbon content i.e. 3% as compared to pig iron.

The Zr andTi are purified by the help of Arkel Method that contain the following reaction: 

Zr (s) + 2I2   ZrI4 ( g)  Zr Pure  (s) + 2I2

Ti + 2I2  TiI4  Ti + 2I2

Here we obtain Zr and Ti as a pure form of solid when purified using the Arkel method.

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alok kumar singh

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33. Option (ii) and (iv)

From Fig.6.1, at point B, all three lines, i.e. for the lines for all three given reactions, are below that of the line of reduction of FeO. This means, that the value of ΔG for the equivalent temperature at point B for reduction of FeO is greater than (positive) that of values of ΔG for all three reactions (negative). Thus,  FeO will get reduced by all three reactions at point B. Same is the case with point E as that of point B, the value of ΔG for reduction of FeO at E is greater than the value of ΔG&nb

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alok kumar singh

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32. Option (i)

According to the above graph, at point D the equivalent value of ΔG for the reduction of FeO is approximately 330 units for the particular temperature. Also, for CO the equivalent value of Δ?  at the particular temperature for point D  is around −330 units. Thus, if we calculate the overall value of ΔG for the reduction of FeO with carbon monoxide then it is almost zero at point D.

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