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New answer posted
3 years ago
0 Follower
14 Views
Adv. Ved VinayakLaw educator at Lex Logic You Tube channel.
Contributor-Level 9
You must fall under the OBC-NCL category, I'm certain. You did pretty well in this category relative to the National Testing Agency's cutoff, which is around 67. This suggests to me that you have a strong Probability of being admitted to CSE. Based on your success in this exam, Shiksha has developed a college predictor that will assist you in determining the branch and college you will be admitted to.
https://www.shiksha.com/engineering/jee-main-college-predictor
https://www.shiksha.com/engineering/jee-main-college-predictor
New answer posted
3 years ago
0 Follower
40 Views
Adv. Ved VinayakLaw educator at Lex Logic You Tube channel.
Contributor-Level 9
You must achieve a score higher than the national testing agency's cutoff percentage in order to be admitted to any NIT. Even if you haven't addressed it here, I'm certain you are aware of your percentile. I've included a link created by Shiksha that will forecast the likely college or NIT you'll go depending on your test scores. https://www.shiksha.com/engineering/jee-main-college-predictor
I wish you well.
I wish you well.
New answer posted
3 years ago
0 Follower
22 Views
Adv. Ved VinayakLaw educator at Lex Logic You Tube channel.
Contributor-Level 9
A well-informed estimate or prediction based on a few prior factors might undoubtedly produce positive outcomes. Shiksha has released a college predictor as a service to you. Based on your category and, of course, your test results, this will forecast the college and the branch that you can get. I've attached it below for your assistance. https://www.shiksha.com/engineering/jee-main-college-predictor
I wish you well.
I wish you well.
New answer posted
3 years ago
0 Follower
51 Views
Adv. Ved VinayakLaw educator at Lex Logic You Tube channel.
Contributor-Level 9
46 percent has been set by the National Testing Agency as the cutoff for your category. You will only be qualified to apply for admission to any NIT or Central Government-funded institution if your percentile is higher than this. A programme developed by Shiksha can forecast the college you will go based on how well you perform on this test. Try it out. I wish you luck.
New answer posted
3 years ago
0 Follower
54 Views
Adv. Ved VinayakLaw educator at Lex Logic You Tube channel.
Contributor-Level 9
Despite the fact that you haven't explicitly said it this way, I must guess that you did fairly well in the JEE Mains examination. Fortunately for you, the minimum 12th grade point average criteria has been waived for this year's admissions procedure, thus you should be qualified to apply. Hope it's helpful. I wish you luck.
New answer posted
3 years ago
0 Follower
192 Views
Adv. Ved VinayakLaw educator at Lex Logic You Tube channel.
Contributor-Level 9
Student must score in the top 99th percentile to qualify into the computer science branch. It's just a straightforward mathematical computation here. 1 percentile indicates that 1 percent of the students scored higher than you. A percentile of 99 indicates that, out of the 10 lakh students who took the JEE Mains exam, about 10000 students scored higher than you. If we add up all the seats in all the NITs for this branch, there aren't as many left.
New answer posted
3 years ago
0 Follower
13 Views
Adv. Ved VinayakLaw educator at Lex Logic You Tube channel.
Contributor-Level 9
Yes, on August 11th, a student may register for JEE Advanced. Students from India who took the JEE Mains and placed in the top two and a half Lacs candidates are eligible to take the JEE Advanced. You can get all the information you need regarding this exam at the website I've attached. https://www.shiksha.com/engineering/jee-advanced-exam
I wish you well.
I wish you well.
New answer posted
3 years ago
0 Follower
53 Views
Adv. Ved VinayakLaw educator at Lex Logic You Tube channel.
Contributor-Level 9
It is very difficult to translate % into ranks. This is the case since no one is aware of the number of pupils who fall within a few percentiles of each other or at the same percentile. Only the National Testing Agency has access to all the information, and they will definitely release it soon after the second session of the JEE Mains examination is completed. Just be patient for a few more days, and you will receive your results.
New answer posted
3 years ago
0 Follower
16 Views
Adv. Ved VinayakLaw educator at Lex Logic You Tube channel.
Contributor-Level 9
Different coaches use various tactics to help you pass these two difficult yet extremely essential exams. Fundamentally, you must make sure that while completing your 12th grade, you make an effort to comprehend and master various subjects so that it will be simpler for you to respond to analytical questions in this exam. You must set aside time each day for all of your studies and schedule time for practice exams. These tests assist students in identifying their areas of weakness and implementing the appropriate corrective measures. Attending coaching lessons will almost always teach you how to answer questions within the allotted tim
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New answer posted
3 years ago
0 Follower
180 Views
Adv. Ved VinayakLaw educator at Lex Logic You Tube channel.
Contributor-Level 9
Hello, The percentile one achieves in the exam determines one's ranking in JEE Mains. Additionally, the national testing agency chooses the student's two best performances to calculate their percentile. The calculation here goes all the way to 7 decimal places. NTA will release the JEE Mains results once both testing sessions are over, and Devil will simultaneously release the percentile and ranking that each student achieved in this exam. Since the necessary data is solely and exclusively available through NTA no one else can calculate the percentile.
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