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New answer posted

9 months ago

0 Follower 5 Views

R
Rupesh Katariya

Contributor-Level 10

Hello! With a JEE rank around 8.2 lakh, it might be tough to get into top-tier government colleges, but don't worry—you still have good private college options for B.Tech in CSE with decent placements. You can consider:

  • Lovely Professional University (LPU)

  • Chandigarh University

  • Amity University (Noida)

  • Parul University (Vadodara)

  • MIT ADT (Pune)

These colleges offer CSE course  with  a good campus placements if you work on your skills (DSA, web development etc. ).

New answer posted

9 months ago

0 Follower 1 View

C
Chanchal Patra

Contributor-Level 8

If you don't meet the official cutoff, which is the minimum required to be on the merit list and be eligible for registration tests, you can't take part in the NCHMCT MSc JEE 2025 counselling. To participate you need to fulfil following criteria:

  • Cutoff Point:  The lowest qualifying score or rank required for admission eligibility is known as the NCHMCT JEE cutoff.  Counselling is only available to people who reach or exceed this threshold. Those who pass the cutoff are added to the merit list, where they can register, fill out forms, and take part in seat distribution.
  • No Counselling If There Is No Cutoff:  The portal wil
...more

New question posted

9 months ago

0 Follower 2 Views

New answer posted

9 months ago

0 Follower 1 View

P
Pallavi Pathak

Contributor-Level 10

The capacitive reactance is equal to the inductive reactance at resonance:

  X L = X C ? ? = 1 L ? C

New question posted

9 months ago

0 Follower 10 Views

New answer posted

9 months ago

0 Follower 4 Views

P
Pallavi Pathak

Contributor-Level 10

In an AC circuit, the power factor cos? measures the efficiency of power usage. Between the current and voltage, it is the cosine of the phase angle. A power factor of 1 means all the supplied power is used effectively and a low power factor means more energy is wasted.

Average power:

P = V rms I rms cos ? ?

New answer posted

9 months ago

0 Follower 1 View

P
Pallavi Pathak

Contributor-Level 10

The alternating current's RMS (Root Mean Square) value or voltage offers the equivalent DC value that would generate the same power in a resistive circuit. The RMS is used in most practical measurements and is calculated as:

  I rms = I 0 2 , V rms = V 0 2

Where ?0 and ?0 are the peak current and voltage, respectively.

New answer posted

9 months ago

0 Follower 1 View

P
Pallavi Pathak

Contributor-Level 10

Students can expect conceptual questions on Faraday's and Lenz's Laws, derivations involving EMF, flux calculations, and application-based questions like the functioning of generators or transformers. Numerical problems involving   and time-varying magnetic fields are also frequently included.

New answer posted

9 months ago

0 Follower 2 Views

P
Pallavi Pathak

Contributor-Level 10

Lenz's law is used for devices like eddy current brakes, induction cooktops, and metal detectors. For example in induction cooktops, the currents in the cookware are induced by the changing magnetic fields. It generates the heat due to resistance. It is based on Lenz's law which follows the opposing nature of the induced current.

New answer posted

9 months ago

0 Follower 36 Views

P
Pallavi Pathak

Contributor-Level 10

The negative sign in Faraday's Law of Electromagnetic Induction is extremely significant as it gives the direction of the induced EMF. Faraday's law is based on Lenz's law which reflects the principle of conservation of energy. It says that the induced EMF always opposes the magnetic flux changes that cause it. Following is the Faraday's law equation:

  ? = ? d ? B d t

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