Maths NCERT Exemplar Solutions Class 12th Chapter Twelve

Get insights from 47 questions on Maths NCERT Exemplar Solutions Class 12th Chapter Twelve, answered by students, alumni, and experts. You may also ask and answer any question you like about Maths NCERT Exemplar Solutions Class 12th Chapter Twelve

Follow Ask Question
47

Questions

0

Discussions

3

Active Users

0

Followers

New question posted

2 months ago

0 Follower 1 View

New question posted

2 months ago

0 Follower 2 Views

New answer posted

2 months ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

Let TV (r) denotes truth value of a statement r .

 Now, if TV (p)=TV (q)=T

TVS1=F

Also, if TV (p)=T and TV (q)=F

TVS2=T

New question posted

2 months ago

0 Follower 1 View

New answer posted

2 months ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

x=10

x? =63+a+b8=10

a+b=17

Since, variance is independent of origin.

So, we subtract 10 from each observation.

So,  σ2=13.5=79+ (a-10)2+ (b-10)28

a2+b2-20 (a+b)=-171

a2+b2=169

From (1) and (2) ; a=12 and b=5

New answer posted

2 months ago

0 Follower 7 Views

P
Payal Gupta

Contributor-Level 10

1 < | z 3 + 2 i | < 4

z = a + i b a , b I              

⇒ 1 < (a 3)2 + (b + 2)2 < 16

in equivalent to 1 < 2 + β2 < 16  α = a 3 l               

( ± 2 , 0 ) ( ± 3 , 0 ) , ( 0 , ± 2 ) ( 0 , ± 3 )             β = b + 2 l

Total 40 such points are possible

New answer posted

2 months ago

0 Follower 3 Views

A
alok kumar singh

Contributor-Level 10

We have,  1-  (probability of all shots result in failure)  > 1 4

1 - 9 10 n > 1 4 3 4 > 9 10 n n 3

New answer posted

2 months ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

 Since,  limx0? f (x)x exist f (0)=0

Now,  f' (x)=limh0? f (x+h)-f (x)h=limh0? f (h)+xh2+x2hh ( take y=h)

=limh0? f (h)h+limh.0? (xh)+x2

f' (x)=1+0+x2

f' (3)=10

New answer posted

2 months ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

D=1-232111-7a=0a=8

also,  D1=9-23b1124-78=0b=3

hence,  a-b=8-3=5

New answer posted

2 months ago

0 Follower 3 Views

A
alok kumar singh

Contributor-Level 10

D1=-74-181515b6=0b=-3D=14-1315ab6=021a-8b-66=0P:2x-3y+6z=15

so required distance =217=3

Get authentic answers from experts, students and alumni that you won't find anywhere else

Sign Up on Shiksha

On Shiksha, get access to

  • 65k Colleges
  • 1.2k Exams
  • 688k Reviews
  • 1800k Answers

Share Your College Life Experience

×
×

This website uses Cookies and related technologies for the site to function correctly and securely, improve & personalise your browsing experience, analyse traffic, and support our marketing efforts and serve the Core Purpose. By continuing to browse the site, you agree to Privacy Policy and Cookie Policy.