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New answer posted

a year ago

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V
Vishal Baghel

Contributor-Level 10

Equation of plane r to line x 3 2 = x 1 1 = x 2 1 and passes through the point

(2, 3, -1) is 2(x – 2) + 1(y – 3) + 1 (z + 1) = 0

=> 2x + y + z – 6 = 0         .(i)

Hence point (1, 2, 2) satisfies equation (i)

z = 1 1 c o s θ + 2 i s i n θ = 1 c o s θ 2 i s i n θ ( 1 c o s θ ) 2 ( 2 i s i n θ ) 2 = 2 s i n 2 θ 2 2 i s i n θ ( 1 c o s θ ) 2 + 4 s i n 2 θ      

R e ( z ) = 2 s i n 2 θ 2 4 s i n 2 θ 2 ( s i n 2 θ 2 + 4 c o s 2 θ 2 ) = 1 2 ( 1 + 3 c o s 2 θ 2 ) = 1 5 c o s 2 θ 2 = 1 2   

θ = π 2 0 π 2 s i n x d x = 1

New answer posted

a year ago

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A
alok kumar singh

Contributor-Level 10

2n = 4096 -> n = 12

12C6 = 924 (the greatest coefficient)

New answer posted

a year ago

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A
alok kumar singh

Contributor-Level 10

6 3 = 2 t t = 1

 ->R (-1,0)

    P R 2 + R Q 2 = 2 0 + 5 = 2 5          

 

New answer posted

a year ago

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A
alok kumar singh

Contributor-Level 10

xf (x) + 2 = λ (x – 2) (x – 3) (x – 4) (x – 5)

x = 0 λ = 1 6 0                

x = 10 -> 10f (10) = 26

New answer posted

a year ago

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A
alok kumar singh

Contributor-Level 10

Kindly go through the solution

 

New answer posted

a year ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

  f ( x ) = { 2 x 2 + 3 , 2 < x < 1 x 2 , 1 x < 0 3 2 1 , 0 x < 1 x 2 3 + 1 2 , 1 x < 2

f ( 1 ) = f ( 1 + ) = f ( 1 ) = 1                

f ( 1 + ) = f ( 1 ) = 1 2 2                

Points of discontinuity

x = 0, 1

New answer posted

a year ago

0 Follower 39 Views

A
alok kumar singh

Contributor-Level 10

v = l a + m b  

= ( 2 l + m , l + 2 m , 2 l = m )               

  v . ( 3 , 2 , 1 ) = 0 l = 4 m . . . . . . . ( i )              

  | v . a ^ | = 1 9 9 l 2 m = 5 7 . . . . . . . . ( i i )              

(i) & (ii) Þ l = 6, m =   3 2

2 v = ( 2 1 , 1 8 , 2 7 )              

| 2 v | 2 = 1 4 9 4            

New answer posted

a year ago

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A
alok kumar singh

Contributor-Level 10

l i m x 1 x n f ( 1 ) f ( x ) x 1  

= l i m x 1 9 x n ( x 6 + 2 x 4 + x 3 + 2 x + 3 ) x 1                

= 9n – 19 = 44 -> n = 7

New answer posted

a year ago

0 Follower 27 Views

A
alok kumar singh

Contributor-Level 10

ar (ABC) = 4ar (DEF)

= 4 * 1 2 * | 2 ( 2 5 ) + 1 ( 5 3 ) + 7 ( 3 2 ) | = 2 | 6 + 2 + 7 | = 6

 

New question posted

a year ago

0 Follower 4 Views

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