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New answer posted

5 months ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

The given system of eqn in matrix form is AK = B

= 5 x 28 -13 + 4 x (-9)

= 140 - 13 - 76

= 51 ≠ 0 .

The given system of eqn are consistent

New answer posted

5 months ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

The given system of eqn using matrix form can be written as AK = B

= 3 ( 0 5 ) + 1 ( 0 + 3 ) 2 ( 0 6 )

= -15 + 3 + 12

 = -15 + 15

= 0

New answer posted

5 months ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

The given system of eqn using matrix method can be expressed as

                 AK = B

= ( 6 a 2 a ) ( 4 a 2 a ) + ( 2 a 3 a )

= 4a – 2a – a

= a ≠ 0.

Hence, the given system of eqn is consistent

New answer posted

5 months ago

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V
Vishal Baghel

Contributor-Level 10

The given system of equation can be written in the form AK = B

Hence the given system of eqn are inconsistent.

New answer posted

5 months ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

The given system of eqn can be written in the form AK = B where

Now, = 2 – (-1) = 2 + 1 = 3 ≠ 0.

∴ The system of eqnis consistent.

New answer posted

5 months ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

The given system of equation can be written in the form of AK = B

Now,  = 3 * 1 - 2 * 2 = 3 - 4 = -1 ≠ 0.

∴ The system has unique soln  and hence equation are consistent

New answer posted

5 months ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

Given, A is an invertible matrix of order 2.

∴ Option (B) is correct.

New answer posted

5 months ago

0 Follower 3 Views

V
Vishal Baghel

Contributor-Level 10

Kindly go through the solution

New answer posted

5 months ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

Given, A=  [11123213]

New answer posted

5 months ago

0 Follower 3 Views

V
Vishal Baghel

Contributor-Level 10

Kindly go through the solution

⇒ b = 1

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