Ncert Solutions Chemistry Class 12th

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A
alok kumar singh

Contributor-Level 10

This is electrophilic substitution reaction which is determine by electronic effect of

 

 

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alok kumar singh

Contributor-Level 10

Cast iron is used to make wrought iron and steel.

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alok kumar singh

Contributor-Level 10

E2 elimination. Most acidic proton is removed. Fluorine is more electronegative.

 

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alok kumar singh

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Seliwanoff's test distinguishes aldoses from ketoses. Sucrose hydrolyzes to glucose (aldose) and fructose (ketose). Fructose gives a red color.

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alok kumar singh

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gives iodoform test and slow Lucas test, so it's a methyl secondary alcohol. D gives fast Lucas test, so it's a tertiary alcohol. The Grignard products must be tertiary and secondary alcohols. So A and B must be an aldehyde and a ketone.

 

 

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alok kumar singh

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. [XeF? ]? has 7 electron pairs (5 bonding, 2 lone), pentagonal planar. XeO? F? has 5 electron pairs (trigonal bipyramidal).

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Raj Pandey

Contributor-Level 9

Sol. (x/m) = k (P)¹/?
log (x/m) = logk + 1/n logP
Slope = 1/n = 2 So n = 1/2
Intercept ⇒ logk = 0.477 So k = Antilog (0.477) = 3
So (x/m) = k (P)¹/? = 3² = 48

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alok kumar singh

Contributor-Level 10

Reaction (1) is SN1 (rate independent of [OH? ]). Reaction (2) is E2 (rate depends on [OH? ]).
Statement (B) is correct. Changing concentration of base will have no effect on reaction (1).

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Raj Pandey

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Cesium has lowest ionisation enthalpy and hence it can show photoelectric effect to the maximum extent hence it is used in photo electric cell.

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