Ncert Solutions Chemistry Class 12th
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New answer posted
a month agoContributor-Level 10
ΔG° = –RT * 2.303 log K
–nFE° = +RT * 2.303 log K
2 * 96500 * 0.295 = 8.314 * 298 * 2.303 log10 K
10 = log10 K = 1010
New answer posted
a month agoContributor-Level 10
It has chiral centre and differently di substituted double bonded carbon atoms.
New answer posted
a month agoContributor-Level 10
Glucose and fructose are functional group isomers of each other
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