Ncert Solutions Maths class 11th

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Payal Gupta

Contributor-Level 10

11. Kindly go through the solution

New answer posted

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Payal Gupta

Contributor-Level 10

10. Kindly go through the solution

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4 months ago

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P
Payal Gupta

Contributor-Level 10

9. Kindly go through the solution

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4 months ago

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P
Payal Gupta

Contributor-Level 10

8. Kindly go through the solution

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New answer posted

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Payal Gupta

Contributor-Level 10

It is given that,

IQ = MACA*100…. (1)

and 80  IQ  140 34 ……. (2)

Putting (1) in (2) we get,

80,
MACA*100, 140.

Let x be the mental age for chronological age 12, then we can write,

80,
x12*100, 140.

80*12100x12*100*12100140*12100  (multypling by 12/1200 throughout)

9.6x16.8.

x [9.6, 16.8]

Thus, the required metal age for 12 yes old children is from 9.6 to 16.8.

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4 months ago

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Payal Gupta

Contributor-Level 10

64. Let x litre of water is required to added.

Then, total mixture =(x+1125) litre.

As, 0 % of acid is contained in pure mater (neutral).

 0% of x + 45% of 1125% > 25% of (x+1125)

0*x100+45100*1125>25100(x+1125) (multiplying by 100 throughout)

 

1125(4525)25>25x25 (dividing by 25 throughout)

1125*2025>x

900>x ……(1)

And 0% of x+ 45% of 1125<30 of (x+1125)

0100*x+45100*1125<30100(x+1125)

45*1125<30(x+1125) {multiplying by 100 throughout)

45*1125<30x+30*1125

 45 * 1125 – 30 * 1125 < 30x

1125(4530)30<30x30 {dividing by 30 throughout}

1125*1530<x

562.5

From (1) and (2),

562.5

Thus, the water to be added has to be more than 562.5 litre but less than 900 litres.

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4 months ago

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Payal Gupta

Contributor-Level 10

63. Let x litre of 20 % boric acid solution is required to added. Since, we have 640 litres of 8 % boric acid solution.

Total mixture will have (x + 640) litre.

2%of x+ 8%of640>4%of(x+640).

2x100+8*640100>4*(x+640)100

 2x100*1002+8100*640*1002>4100*(x+640)*1002 (multiplying throughout by 1002 )

x+2560>2(x+640)

2x+2560>2x+1280

25601280>2xx

1280>x (1)

And 2 % of x + 8 % of 640 < 6 % of (x+ 640)

2x100+8100*640<6100(x+640)

2x+8*640<6x+6*640(multiplyingby 100throughout)

8*6406*640<6x2x

640(86)<4x

640*24<4x44 (dividing by 4 throughout)320<x(2)

So, from (1) and (2) we get,

320

Thus, the number of litre of 2 % boric acid solution will have to be more than 320 litres but less than 1280 litres.

 

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4 months ago

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Payal Gupta

Contributor-Level 10

62. It is given that

68< F<77.

Putting f=95c+32 we get,

68<95c+32<77.

6832<95c+3232<7732.  (Subtracting 32 throughout)

36<95c<45

Multiplying by 59 throughout,

36*59<95*c*59<45*59

20<c<25

Hence, the required range of temperature is between 20°25°.

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4 months ago

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