Ncert Solutions Physics Class 12th

According to Gauss’s law for magnetism, the net magnetic flux through any closed surface is zero.

$?\mathbf{B}\cdot dA=0$

It states that all magnetic field lines must enter and exit from a surface. In this way, it differs from electric charges, which can exist independently as positive and negative.

Magnetism is the force exerted by a magnet. It comes when the magnet attracts or repulses an object. For example, a magnet sticks to certain objects because the magnetic force or magnetism pulls it.

If you want the Current Electricity Class 12 important questions, then check the Class 12 Physics previous year question paper pdf. Also, focusing on the Class 12 Physics past 5 years of exam questions to identify the current electricity class 12 important questions. Well, we have framed all the imp

Before attempting the NCERT solutions PDF, solve the textbook exercise questions. Hereafter, verify your answer using the NCERT Class 12 Physics Ch 3 solutions pdf. Following a systematic approach to solve a problem will help to score good marks in the CBSE Class 12 board exam.

Class 12 Physics Chapter 3 Current Electricity is important for the board exam. The weightage of the chapter is 8-10%. When you practice the Current Electricity class 12 NCERT solutions, you get an overview of your preparation. If you are lacking in any concept, then it helps to build the conceptual

The topics focused on while preparing the Current Electricity NCERT solutions are:

• Ohm's law

• Drift velocity

• Resistivity vs temperature

• Combination of cells

• Kirchhoff's rules and 

• Wheatstone bridge

Important topics in NCERT class 12 Physics chapter 13 nuclear include atomic structure, nuclear binding energy, radioactivity, Nuclear Fission, and nuclear fusion. These concepts are fundamental to understanding the behaviour and properties of atomic and nuclear matter and are crucial for both the b

2.16 Electric field on one side of a charged body is $E_1$ and electric field on the other side of the same body is $E_2.$ If infinite plane charged body has a uniform thickness, then electric field due to one surface of the charged body is given by,

$\stackrel{?}{E_1}$ = $\frac{\sigma }{2{\epsilon }_0}\stackrel{?}{n}$ ………….(i)

Where,

$\stackrel{?}{n}$ =

2.31 The force between two conducting spheres is not exactly given by the expression ${\mathit{Q}}_1{\mathit{Q}}_2$ /4 $\mathit{?}{\mathit{?}}_0{\mathit{r}}^2$ , because there is non-uniform charge distribution on the spheres.

Gauss's law will not be true, if Coulomb's law involved $\frac{1}{r^3}$ dependence, instead of $\frac{1}{r^2}$ , on r

Yes. If a small t

13.28 The equation for deuterium-tritium fusion is given as:

${}_1{}^{2}H+{}_1{}^{3}H\to {}_2{}^{4}He+n$

 It is given that

Mass of ( ${}_1{}^2\mathrm{H}),\mathrm{}{\mathrm{m}}_1$  = 2.014102 u

Mass of ( ${}_1{}^3\mathrm{H})$ , ${\mathrm{m}}_2=\mathrm{}$ 3.016049 u

Mass of ( ${}_2{}^{4}He),m_3$  = 4.002603 u

Mass of ( ${}_0{}^{1}n),m_4$ = 1.008665 u

Q-value of the given D-T reaction is:

Q = $\left[{\mathrm{m}}_1+{\mathrm{m}}_2-m_3-m_4\right]c^2$

= $\left[2.014102+3.016049-4.002603-1.008665\right]c^{2}u$

= 0.018883 $c^{2}u$

= 17.59 MeV

Radius of the deuterium and tritium, r $\approx 2.0fm$