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New answer posted

5 months ago

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M
Md Shahzad

Contributor-Level 10

NCERT books are very important for MPBSE 12th exams because most questions come from these books. They explain topics in a simple and clear way. Studying them properly helps you score better. Do not ignore the examples and exercises given at the end of each chapter. Always revise the NCERT content before trying other reference books.

New answer posted

5 months ago

0 Follower 4 Views

Shiksha Ask & Answer
Jasleen Taneja

Contributor-Level 10

No, the CISCE board does not require the use of NCERT books for ISC exams. While some ISC students may find NCERT books helpful for understanding concepts or preparing for entrance exams, the ISC curriculum has its own prescribed textbooks and doesn't mandate NCERT books as a requirement. 

New answer posted

5 months ago

0 Follower 2 Views

H
Himanshi Singh

Beginner-Level 5

To understand this, Assume you have a bucket that has infinite number of apples and if your mother asks "give me the apple". How will you figure out which one is "The Apple", she is asking for.

Similarly any inversre trigonometric functions behaves like a Many-one Function; which means,

For Example sin? ? 1 (23)\sin^ {-1}\left (\frac {2} {3}\right) can have many solutions, we need to fix one solutions which can be used as standerd value for the function.

  • A standerd value (Angles) of any inverse trigonometric value lies between a fiexed range is known as principal value. 

For Ex; The value of sin? ? 1 (23)\sin^ {-1}\left (\frac {2} {3}\right) will always lie between –? /2 to? /2.


y = sin ?1 ( 2 3 ) ? sin ( y ) = 2 3 ? y ? [ ? ? 2 , ? 2 ]  

New answer posted

5 months ago

0 Follower 9 Views

B
Bhumika Lama

Contributor-Level 7

To prepare,  it's recommended to study NCERT books for Classes 11 and 12, as well as NCERT materials. The written exam oof NDA comprises two papers-Maths and GAT. The total marks allotted to the NDA written exam are 900. To clear the concept of the topics given in the syllabus, candidates must refer to good NDA books.

New answer posted

5 months ago

0 Follower 3 Views

S
Shiksha Vimal

Beginner-Level 5

NCERT textbooks for Classes 11 and 12 are crucial for CUET UG 2025, as they cover fundamental concepts and the exam's prescribed syllabus. However, to score well in the exam, students should also refer to additional books that offer advanced problems and varied practice exercises, especially for subjects like Physics and Chemistry.

Reference books like H.C. Verma's Concepts of Physics and OP Tandon's Organic Chemistry provide additional questions that help students practice for higher difficulty levels that might be covered in CUET Science paper.

New answer posted

5 months ago

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J
Jaya Sinha

Beginner-Level 5

As per the NCERT Textbooks

“An integrated Chip consists of many passive and active components fabricated on a single chip of silicon. these ICs are compact, low-cost, and highly reliable. They consume less power and have high speed.”

These ICs are used in majority of our daily use electronics and all advance electronics. 

New answer posted

5 months ago

0 Follower 1 View

S
Satyendra Dhyani

Beginner-Level 5

Nuclear Binding Energy is the amount of energy required to completely dismantle a nucleus into its individual protons and neutrons which is equivalent to the amount of energy to form a nucleous from its constituent nucleons (protons and neutrons).

Binding energy is calculated using Einstein's mass-energy equivalence relation:

B.E.=? m? c2B.E. = \Delta m \cdot c^2Where:

  • ? m\Delta m = mass defect (in kg or amu)

  • cc = speed of light (3*108? m/s) (3 \times 10^8 \, \text {m/s})

New answer posted

5 months ago

0 Follower 3 Views

P
Pallavi Pathak

Contributor-Level 10

The compound microscope comprises two convex lenses - the eyepiece (lower power) and the objective (high power, short focal length). The objective forms a magnified, inverted, and real image of a small object placed just beyond its focal point. Magnifying power is M = (L/f? ) * (D/f? ), where f? is the objective's focal length, L is the tube length, and f? is the eyepiece's focal length. This image acts as the object for the eyepiece.

New answer posted

5 months ago

0 Follower 2 Views

P
Pallavi Pathak

Contributor-Level 10

The formula says that for a thin lens, the focal length (f) to its refractive index (? ) and radii of curvature (R? , R? ). Let a thin lens with surfaces of radii R? (first surface) and R? (second surface). We can use the refraction formula to calculate the image formation by the first surface. Following is the formula -? /v -? /u = (? -? )/R. Then we can combine both refractions and assume a lens in air (? = 1).

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