Photoelectric Effect

Maximum wavelength of light source such that photoelectron can be ejected from material of work function 3 eV is

In a photoelectric experiment, frequency f = 1.5f₀ (f₀ : threshold frequency). If the frequency of light is changed to f/2, then photocurrent becomes (intensity of light has doubled)

A photocell works on the principle of

The work function of a metal is w₀ and l is wavelength of incident radiation. There is no emission of photoelectron when

The work function of a metal is w0 and $$ $\lambda$ is wavelength of incident radiation. There is no emission of photoelectron when

Two stream of photons, possessing energies equal to twice and ten times the work function of metal are incident on the metal surface successively. The value of ratio of maximum velocities of the photoelectrons emitted in the two respective cases is x : y. The value of x is………

The electric field at a point associated with a light wave is given by

E = 200 $\left[sin\left(6*10^{15}\right)t+sin\left(9*10^{15}\right)t\right]V{m}^{-1}$  

Given : h = 4.14 * 10-¹⁵ eVs

If the light fall on a metal surface having a work function of 2.50 eV, the maximum kinetic energy of the photoelectrons will be

The electric field at a point associated with a light wave is given by

E = 200 $\left[sin\left(6*10^{15}\right)t+sin\left(9*10^{15}\right)t\right]V{m}^{-1}$  

Given : h = 4.14 * 10^-15 eVs

If the light fall on a metal surface having a work function of 2.50 eV, the maximum kinetic energy of the photoelectrons will be

Figure shows the anode potential vs photo-current graph when photons of 6 eV are incident on cathode in a photoelectric experiment set-up. In the same experimental set-up, if photons of 8 eV and same intensity are incident on cathode, then anode-potential vs photo-current graph will be (assume 100% efficiency of photons to eject photo-electrons in both cases)

When monochromatic light of wavelength 620 nm is used to illuminate a metallic surface, the maximum kinetic energy of photoelectrons emitted is 1 eV. Find the maximum kinetic energy of photoelectron emitted (in eV) if a wavelength of 155 nm is used on the same metallic surface. (hc = 1240 eV-nm)