Physics Atoms

Kindly go through the solution 

Change in surface energy = work done

$\left|\Delta E_0\right|=\left(-136\left\{1-\frac{1}{4}\right\}\right)eV$

|DE₀| = –10.2

$\lambda =\frac{12400}{10.2}*10^{-10}m$

$\rho =\frac{h}{\lambda }=\frac{6.63*10^{-34}*10.2}{12400*10^{-10}}$                  

$?$ $mv=\frac{h}{\lambda }$            

  $1.8*10^{-27}$           

$v=\frac{6.63*10.2*10^{-34}}{12400*10^{-10}}$

$v=\frac{6.63*10.2}{12400*1.8}*10^3$            

$=\frac{6.63*102}{124*1.8}=3.02$ ]

= 3 m/s

$-0.85=\frac{-13.6}{n^2}$  

n = 4

Number of transitions = $\frac{4*3}{2}=6$  

Kinetic energy: Potential energy = 1 : –2

For 3 ->2 transitions

            DE = 13.6   $\left(\frac{1}{4}?\frac{1}{9}\right)$

            = 13.6 *   $\frac{5}{36}$

            = 1.88 eV

Kindly go through the solution

rⁿ? µn²

Nice Question! In this case, the matter wouldn't even exist. Atoms will exhibit non-uniform energy levels and can easily jump between different orbitals, leading to instability in the energies. This will lead to an unstable spectra and anything would, ;t exist today in the way we know it to be.