Physics Magnetism and Matter

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New answer posted

2 months ago

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S
Swayam Gupta

Contributor-Level 6

According to Gauss's law for magnetism, the net magnetic flux through any closed surface is zero.

? B d A = 0

It states that all magnetic field lines must enter and exit from a surface. In this way, it differs from electric charges, which can exist independently as positive and negative.

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2 months ago

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S
Swayam Gupta

Contributor-Level 6

Magnetism is the force exerted by a magnet. It comes when the magnet attracts or repulses an object. For example, a magnet sticks to certain objects because the magnetic force or magnetism pulls it.

New answer posted

2 months ago

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V
Vishal Baghel

Contributor-Level 10

For permanent magnetic Y is good choice, As it has very high coercivity (comparitively)

New answer posted

2 months ago

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V
Vishal Baghel

Contributor-Level 10

  • Concept involved: Electric and magnetic field lines
  • Topic: Magnetics and Magnetic Material
  • Difficulty level: Moderate
  • Point of Error: Fact

New answer posted

2 months ago

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R
Raj Pandey

Contributor-Level 9

Magnetic field at centre of a solenoid is proportional to the current through it. Current through C will be one-third of the current through A. So
Magnetic field at the centre of C = 3/3 = 1T.

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A
alok kumar singh

Contributor-Level 10

Kindly go through the solution

 

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V
Vishal Baghel

Contributor-Level 10

From aerie's law x = c/r
I = xH
I? = x? H?
I? = x? H?
I? /I? = x? H? /x? H?
I? /I? = T? H? /T? H? = (4 x 0.3)/ (24 x 0.4) = 1/8
I? = T? /8 = 6/8 = 0.75

New answer posted

2 months ago

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alok kumar singh

Contributor-Level 10

 τ? = μ? * B?
⇒ 0.018 = μ(0.06)(sin 30°)
⇒ μ = 0.6
⇒ Work = Uf – Ui
⇒ 2μB
⇒ 7.2 * 10?² J.

New answer posted

2 months ago

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V
Vishal Baghel

Contributor-Level 10

τ ? = μ ? * B ?

0.018 = μ ( 0.06 ) s i n ? 30 ? μ = 0.6   Work   = U f - U i 2 μ B 7.2 * 10 - 2 J .

New answer posted

2 months ago

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A
alok kumar singh

Contributor-Level 10

Dimension of charge: q = [AT]
Dimension of current I = [A]
Dimension of permeability μ? = [MLT? ²A? ²]
Dimension of momentum: [MLT? ¹]
Let P = q? μ? I? = [AT]? [MLT? ²A? ²]? [A]?
MLT? ¹ = M? L? T? ²? A? ²?
Comparing powers:
y = 1
x - 2y = -1 ⇒ x - 2 (1) = -1 ⇒ x = 1
x - 2y + z = 0 ⇒ 1 - 2 (1) + z = 0 ⇒ z = 1
Hence, the quantity is q¹μ? ¹I¹, or qμ? I.

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