Physics Magnetism and Matter

Match List-I with List-II.

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Match List-I with List-II.

List-I List-II

(Material) (Susceptibility ( $χ$ ))

A. Diamagnetic I. $χ = 0$

B. Ferromagnetic II. $0 > x \geq - 1$

C. Paramagnetic III. $χ ? 1$

D. Non-magnetic IV. $0 < χ < ε$ (a small positive number)

Choose the correct answer from the options given below

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Contributor-Level 10

(Material) (Susceptibility ( $χ$ )

Diamagnetic (II) $0 > χ \geq - 1$

Ferromagnetic (III) $χ ? 1$

Paramagnetic (IV) $0 < χ < ε$

Non-magnetic (I) $χ = 0$

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New answer posted

a month ago

In a uniform magnetic field of 0.049 T, a magnetic needle performs 20 complete oscillations in 5 seconds as shown. The moment of inertia of the needle is $9.8 * 1 0^{- 6} kg m^{2}$ . If the magnitude of magnetic moment of the needle is $x * 1 0^{- 5} A m^{2}$ , then the value of ' $x$ ' is :

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Physics Magnetism and Matter Magnetism and Matter

Contributor-Level 10

Time period of Oscillation, $T = 2 π \sqrt[]{\frac{I}{M B}}$

$\Rightarrow \frac{1}{4} = 2 π \sqrt[]{\frac{9.8 * 1 0^{- 6}}{M * 0.049}}$

$\Rightarrow \frac{1}{16} = 4 π^{2} * \frac{9.8 * 1 0^{- 6}}{M * 49 * 1 0^{- 3}}$

$\Rightarrow M = \frac{4 π^{2} * 9.8 * 1 0^{- 6}}{49 * 1 0^{- 3}} * 16$

$= \frac{4 π^{2} * 9.8 * 16 * 1 0^{- 3}}{49}$

$= 12.8 π^{2} * 1 0^{- 3} * 1 0^{- 2} * 1 0^{2}$

$= 1280 π^{2} * 1 0^{- 5} A m^{2}$

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New answer posted

a month ago

Choose the correct option:

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Physics Magnetism and Matter Magnetism and Matter

Contributor-Level 10

True dip is less than the apparent dip.

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New answer posted

a month ago

Statement I : The ferromagnetic property depends on temperature. At high temperature, ferromagnet becomes paramagnet.

Statement II : At high temperature, the domain wall are of a ferromagnetic substance increases.

In the light of the above statements, choose the most appropriate answer from the options given below:

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Contributor-Level 10

I : at high temperature, ferromagnet becomes paramagnet.

II : at high temperature, domains of ferromagnet will break

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New answer posted

2 months ago

The magnetic susceptibility of a material of a rod is 499. Permeability in vacuum is 4π * 10^-⁷ H/m. Absolute permeability of the material of the rod is:

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Contributor-Level 10

Given $_{}^{}$ $χ = 499 a n d μ_{0} = 4 π * 1 0^{- 7} H / m$

As we know that

$μ_{r} = 1 + χ = 1 + 499 = 500$ Relative permeability

Absolute permeability = $μ = μ_{r} μ_{0} = 500 * 4 π * 1 0^{- 7} = 2 π * 1 0^{- 4} H / m$

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New answer posted

2 months ago

Following plots show Magnetization (M) vs Magnetising field (H) and Magnetic susceptibility $(χ)$ vs temperature (T) graph:

Which of the following combination will be represented by a diamagnetic material?

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Physics Magnetism and Matter Magnetism and Matter

Contributor-Level 10

Magnetization (M) is directly proportional to magnetizing field and magnetic susceptibility does not depend on temperature so option 3 is correct.

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New answer posted

2 months ago

A long solenoid with 1000 turns/m has a core material with relative permeability 500 and volume 10³ cm³. If the core material is replaced by another material having relative permeability of 750 with same volume maintaining same current of 0.75A in the solenoid, the fractional change in the magnetic moment of the core would be approximately $(\frac{x}{499}) .$ Find the value of x.

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Contributor-Level 10

$\frac{Δ M}{M} = \frac{Δ μ}{μ} = \frac{250}{500} = \frac{1}{2}$

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New answer posted

2 months ago

Following plots show Magnetization (M) vs Magnetising field (H) and Magnetic susceptibility $(χ)$ vs temperature (T) graph:

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Contributor-Level 10

Magnetization (M) is directly proportional to magnetizing field and magnetic susceptibility does not depend on temperature so option 3 is correct.

0 0

New answer posted

2 months ago

Two short magnetic dipoles m1 and m2 each having magnetic moment of 1 Am² are placed at point O and P respectively. The distance between OP is 1 meter. The torque experienced by the magnetic dipole m2 due to the presence of m₁ is____________ * 10^-7 Nm.

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