Physics NCERT Exemplar Solutions Class 11th Chapter Six

Get insights from 56 questions on Physics NCERT Exemplar Solutions Class 11th Chapter Six, answered by students, alumni, and experts. You may also ask and answer any question you like about Physics NCERT Exemplar Solutions Class 11th Chapter Six

Follow Ask Question
56

Questions

0

Discussions

3

Active Users

0

Followers

New answer posted

3 months ago

0 Follower 2 Views

P
Payal Gupta

Contributor-Level 10

This is a multiple choice answer as classified in NCERT Exemplar

(b) When two bodies of equal masses collides elastically, their velocities are interchanged.

When ball 1 collides with ball 2 then velocity of ball1, v1 becomes zero and velocity of ball 2, v2 becomes v.

V1=0, V2=v

When ball 2 collides will ball 3 v2 =0, v3=v

New answer posted

3 months ago

0 Follower 2 Views

P
Payal Gupta

Contributor-Level 10

This is a multiple choice answer as classified in NCERT Exemplar

(b) Total energy is E=KE+PE……………1

When particle is at x =xm i.e at extreme position, returns back. Hence at x=xm and x=0 KE=0

From eqn1

E= PE+0 = PE= V (xm)=1/2kxm2

New answer posted

3 months ago

0 Follower 24 Views

P
Payal Gupta

Contributor-Level 10

This is a multiple choice answer as classified in NCERT Exemplar

(c) From conservation of mechanical energy

1 2 m v 2 = m g h

V= 2 g h

Hence speed is same for both stones .

a1=acceleration along inclined plane = gsin θ 1

Similarly for stone a2=gsin θ 2 as θ 2> θ 1, hence a2>a1

New answer posted

3 months ago

0 Follower 2 Views

P
Payal Gupta

Contributor-Level 10

This is a multiple choice answer as classified in NCERT Exemplar

(c) when we are considering the two bodies as system the total external force on the system will be zero . hence total linear momentum of the system remains conserved.

New answer posted

3 months ago

0 Follower 2 Views

P
Payal Gupta

Contributor-Level 10

This is a multiple choice answer as classified in NCERT Exemplar

(c) As the body is  falling freely under gravity, the potential energy decreases and kinetic energy increases but total mechanical energy (PE+KE) of the body and earth system will be constant as external force on the system is zero.

New answer posted

3 months ago

0 Follower 7 Views

P
Payal Gupta

Contributor-Level 10

This is a multiple choice answer as classified in NCERT Exemplar

(c) Work done by the frictional force on the cycle and is equal to -200 * 10 =-2000J

As the road is not moving, hence work done by the cycle on the road = zero.

New answer posted

3 months ago

0 Follower 3 Views

P
Payal Gupta

Contributor-Level 10

This is a multiple choice answer as classified in NCERT Exemplar

When the man is squatting on the ground he is tilted somewhat, hence he also has to balance frictional force besides his weight in this case.

R= reactional force = friction +mg

R>mg

New answer posted

3 months ago

0 Follower 1 View

P
Payal Gupta

Contributor-Level 10

This is a multiple choice answer as classified in NCERT Exemplar

(c) Force between two protons is same as that of between proton and a positron. As positron is much lighter than proton, it moves away through much larger distance compared to proton.

We know that work done = force (distance). As forces are same in case of proton and positron but distance moved by positron is larger, hence work will be more.

New answer posted

3 months ago

0 Follower 1 View

P
Payal Gupta

Contributor-Level 10

This is a multiple choice answer as classified in NCERT Exemplar

(b) When electron and proton are moving under influence of their mutual forces the magnetic forces will be perpendicular to their motion hence no work is done by these forces.

New answer posted

3 months ago

0 Follower 3 Views

P
Payal Gupta

Contributor-Level 10

This is a short answer type question as classified in NCERT Exemplar

Energy given by 1 lit of petrol = 3 * 10 7 J

Efficiency of the car engine=0.5s

Energy used by the car = 0.5 * 3 * 10 7 = 1.5 * 10 7

Total distance travelled s = 15km = 15 * 10 3 m

If f the force of friction= E= f * s

1.5 * 10 7 = f * 15 * 10 3

F= 1.5 * 10 7 15 * 10 3 = 10 3 N

F= 1000 N

Get authentic answers from experts, students and alumni that you won't find anywhere else

Sign Up on Shiksha

On Shiksha, get access to

  • 65k Colleges
  • 1.2k Exams
  • 688k Reviews
  • 1800k Answers

Share Your College Life Experience

×
×

This website uses Cookies and related technologies for the site to function correctly and securely, improve & personalise your browsing experience, analyse traffic, and support our marketing efforts and serve the Core Purpose. By continuing to browse the site, you agree to Privacy Policy and Cookie Policy.