Physics NCERT Exemplar Solutions Class 12th Chapter Fourteen
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New answer posted
3 months agoContributor-Level 10
D1 → forward biased

D2 → Reversed biased
So, current will flow through only D1
= 4 * 10-3 A
= 4mA
New answer posted
3 months agoContributor-Level 10
A = 8 cm
T = 6 sec

q = 60° from A to B
During reaching the point its maximum amplitude from point (A)
t = 1 sec
New answer posted
3 months agoContributor-Level 10
For Transistor
to act as a switch → Saturation & cut – off state
to act as an amplifier → Active Region
New answer posted
4 months agoContributor-Level 10
This is a Multiple Choice Questions as classified in NCERT Exemplar
Answer- (a, d)
Explanation- In reverse biasing, the minority charge carriers will be accelerated due to reverse biasing, which on striking with atoms cause ionization resulting secondary electrons and thus more number of charge carriers.
When doping concentration is large, there will be large number of ions in the depletion
region, which will give rise to a strong electric field.
New answer posted
4 months agoContributor-Level 10
This is a Multiple Choice Questions as classified in NCERT Exemplar
Answer- a, c, d
Explanation-ripple factor is inversely proportional to RL, C and frequency. so to reduce ripple factor all these should be increase.
New answer posted
4 months agoContributor-Level 10
This is a Multiple Choice Questions as classified in NCERT Exemplar
Answer-b, d
Explanation- During regulation action of a Zener diode, the current through the Rs changes and resistance offered by the Zener changes. The current through the Zener changes but the voltage across the Zener remains constant.
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