Physics NCERT Exemplar Solutions Class 12th Chapter Thirteen

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New answer posted

3 months ago

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P
Payal Gupta

Contributor-Level 10

 ΔL  (change in length) =FlAE=mglAE

Δlg

Δl1g1=Δl2g210410=6*105g1

g1=6*104104= 6 m/sec2

New answer posted

3 months ago

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P
Payal Gupta

Contributor-Level 10

 V=d? dt= (15t2+8t+2)

at t = 2 sec, V = (15 * 4 + 8 * 2 + 2)

= 78 V

I=VR=785=15.6A

New answer posted

3 months ago

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A
alok kumar singh

Contributor-Level 10

I= 1 5 3 = 5 A

V B + I * 1 ? 1 5 = v A

v B ? v A = 1 5 ? 5 * 1

= 10v

New answer posted

3 months ago

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A
alok kumar singh

Contributor-Level 10

d c o t θ 2

cot2 30° = x cot2 45°

              x = 3

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3 months ago

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A
alok kumar singh

Contributor-Level 10

A0 = 2.56 * 10-3Ci

              A = 2 * 10-15Ci

              A =   A 0 2 n

                2 * 1 0 5 = 2 . 5 6 * 1 0 3 2 n

                      2n = 128

                      n = 7

             &nbs

...more

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3 months ago

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P
Payal Gupta

Contributor-Level 10

A0 = 2.56 * 10-3Ci

 A = 2 * 10-15Ci

A = A 0 2 n  

2 * 1 0 5 = 2 . 5 6 * 1 0 3 2 n                

2n = 128

n = 7

t = 7 * t1/2

= 7 * 5 = 35 days

New answer posted

3 months ago

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A
alok kumar singh

Contributor-Level 10

Energy released = Binding energy of product – Binding energy of reacts :

ΔE=7.6*4 (1.1*4)

= 26 MeV

New answer posted

3 months ago

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V
Vishal Baghel

Contributor-Level 10

For first line of Lyman

1λ=R (114)=R34

λ=43R

3rd line (Paschen)

1λ3=R (132162)=R9*34

2nd line (B almer)

1λ2=R (122142)=R4*34

a (43R)=203Ra=5

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3 months ago

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A
alok kumar singh

Contributor-Level 10

R=R? A1/3

δ=massvolume=mA43πR3=mA4/3πR03A

 Density is independent of mass number

New answer posted

3 months ago

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A
alok kumar singh

Contributor-Level 10

λ1λ2=h/P1h/P2=11

P1 = P2 as Fnet = 0

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