
Physics NCERT Exemplar Solutions Class 12th Chapter Thirteen Nuclei offers excellent preparation material for the CBSE exams and various entrance exams. The NCERT exemplar has all types of questions from Very-Short Answer Type Questions, Short Answer Type Questions, Long Answer Type Questions and Multiple Choice Questions. Class 12 Science students must practice all these questions to boost their exam confidence and improve their understanding of the various key concepts.
The students can download the Nuclei NCERT PDF to thoroughly practice these questions. It will enhance their problem-solving skills and will also increase their understanding of when and how to use a particular formula or concept. Once downloaded, students can read from this PDF without the requirement of an internet connection. They can also take a printout of the PDF to practice on paper. To further improve their understanding of the key topics related to NCERT Chapter 13 Class 12 Physics, students must also check Chapter 13 Physics Class 12 Nuclei NCERT Solutions. They can also read the NCERT solutions on the Shiksha's page.
- Download PDF of NCERT Exemplar Class 12 Physics Chapter Thirteen Nuclei
- NCERT Exemplar Class 12 Physics Nuclei Short Answer Type Questions
- NCERT Exemplar Class 12 Physics Nuclei Very Short Answer Type Questions
- NCERT Exemplar Class 12 Physics Chapter 13 Long Answer Type Questions
- NCERT Exemplar Class 12 Physics Nuclei Objective Type Questions
- Important Formulas Related to Physics Chapter Thirteen NCERT Exemplar
- JEE Mains Solutions 2022,26th july , physics, second shift
- 27th July 2022 first shift
Download PDF of NCERT Exemplar Class 12 Physics Chapter Thirteen Nuclei
The students must download the Nuclei NCERT PDF from Shiksha's page. The Class 12th Chapter Thirteen Nuclei PDF contains all questions from the NCERT Exemplar book. By solving these questions, students can score high in their CBSE Board exams and other entrance exams such as NEET and JEE examinations. The PDF is well-structured and created by the subject matter expert, and hence it is highly reliable and accurate. Students can easily depend on the Shiksha's NCERT exemplar for their exam preparation. Once the student downloads the PDF, they can access it without the requirement of an internet connection. If they want, they can also take printouts of the PDF and practice the questions on paper. The PDF serves as an excellent exam preparation tool.
NCERT Exemplar Class 12 Physics Nuclei Short Answer Type Questions
Here are the questions and solutions:
Commonly asked questions
Why do stable nuclei never have more neutrons than protons?
Consider a radioactive nucleus A which decays to a stable nucleus C through the following sequence:
A -> B -> C
Here B is an intermediate nuclei which is also radioactive. Considering that there are N0 atoms of A initially, plot the graph showing the variation of number of atoms of A and B versus time.

A piece of wood from the ruins of an ancient building was found to have a 14 C activity of 12 disintegrations per minute per gram of its carbon content. The 14 C activity of the living wood is 16 disintegrations per minute per gram. How long ago did the tree, from which the wooden sample came, die? Given half-life of 14 C is 5760 yr.
NCERT Exemplar Class 12 Physics Nuclei Very Short Answer Type Questions
See below the solutions:
Commonly asked questions
He23 and He13 nuclei have the same mass number. Do they have the same binding energy?
Draw a graph showing the variation of decay rate with number of active nuclei.
Which sample A or B shown in figure has shorter mean-life?

NCERT Exemplar Class 12 Physics Chapter 13 Long Answer Type Questions
These are the LA type questions and solutions:
Commonly asked questions
Sometimes a radioactive nucleus decays into a nucleus which itself is radioactive. An example is
38sulphur 38Cl 38Ar(stable)
Assume that we start 1000 38S nuclei at time t=0. The number of 38Cl is of count zero at t=0 and will be again zero at t= at what value of t, would the number of counts be a a maximum?
Deuteron is a bound state of a neutron and a proton with a binding energy B = 2.2 MeV. A γ-ray of energy E is aimed at a deuteron nucleus to try to break it into a (neutron + proton) such that the n and p move in the direction of the incident γ-ray. If E = B, show that this cannot happen. Hence, calculate how much bigger than B must be E be for such a process to happen.
The deuteron is bound by nuclear forces just as H-atom is made up of p and e bound by electrostatic forces. If we consider the force between neutron and proton in a deuteron as given in the form a coulomb potential but with an effective charge e’.
F= ke’2/r estimate the value of e’/e given that the the binding energy of a duetron is 2.2MeV.
NCERT Exemplar Class 12 Physics Nuclei Objective Type Questions
Find below the solutions:
Commonly asked questions
Suppose we consider a large number of containers each containing initially 10000 atoms of a radioactive material with a half life of 1 year. After 1 year,
(a) All the containers will have 5000 atoms of the material
(b) All the containers will contain the same number of atoms of the material but that number will only be approximately 5000
(c) The containers will in general have different numbers of the atoms of the material but their average will be close to 5000
(d) None of the containers can have more than 5000 atoms
The gravitational force between a H atom and a another particle of mass m will be given newton’s law
F=GMm/r2 where r in km
(a) M=mproton+melectron
(b) M=mproton+melectron-
(c) M is not relate to the mass of the hydrogen atom
(d) M=mproton+melectron-(|V|)= magnitude of the potential energy of electron in H atom.
When a nucleus in an atom undergoes a radioactive decay, the electronic energy levels of the atom
(a) Do not change for any type of radioactivity
(b) Change for α and β-radioactivity but not for γ-radioactivity
(c) Change for α -radioactivity but not for others
(d) Change for β-radioactivity but not for others
Important Formulas Related to Physics Chapter Thirteen NCERT Exemplar
The following are the important formulas of Chapter Thirteen, Physics NCERT Exemplar Nuclei:
Mass-Energy Equivalence
Nuclear Radius Formula
Nuclear Density
Binding Energy (B.E.)
Binding Energy per Nucleon
Radioactive Decay Law
Activity (Rate of Decay)
Half-Life
Mean Life
JEE Mains Solutions 2022,26th july , physics, second shift
JEE Mains Solutions 2022,26th july , physics, second shift
Commonly asked questions
Two projectiles are thrown with same initial velocity making an angle of and with the horizontal respectively. The ration of their respectively ranges will be:
In a Vernier Calipers, 10 divisions of Vernier scale is equal to the 9 divisions of main scale. Then both jaws of Vernier calipers touch each other, the zero of the Vernier scale is shifted to the left of zero of the main scale and 4th Vernier scale division exactly coincides with the main scale reading. One main scale division is equal to 1mm. While measuring diameter of a spherical body, the body is held between two jaws. It is now observed that zero of the Vernier scale lies between 30 and 31 divisions of main scale reading and 6th Vernier scale division exactly coincides with the main scale reading. The diameter of the spherical body will be:
A ball of mass 0.15 kg hits the wall with its initial speed of 12 ms-1and bounces back without changing its initial speed. If the force applied by the wall on the ball during the contact is 100 N, calculate the time during of the contact of ball with the wall.
27th July 2022 first shift
Commonly asked questions
In a meter bridge experiment, for measuring unknown resistance ‘S’, the null point is obtained at a distance 30cm from the left side as shown at point D. If R is 5.6 , then the value of unknown resistance ‘S’ will be ___________
The one division of main scale of Vernier calipers reads 1mm and 10 divisions of Vernier scale is equal to the 9 divisions on main scale, When the two jaws of the instrument touch each other, the zero of the Vernier lies to the right of zero of the main scale and its fourth division coincides with a main scale division. When a spherical bob is tightly placed between the two jaws, the zero of the Vernier scale lies in between 4.1 cm and 4.2cm and 6th Vernier division coincides with a main scale division. The diameter of the bob will be ________× 10-2 cm.
Two beams of light having intensities I and 4I interfere to produce a fringe pattern on a screen. The phase difference between the two beams are p/2 and p/3 at points A and B respectively. The difference between the resultant intensities at the two points is xI. The value of x will be________.
Physics NCERT Exemplar Solutions Class 12th Chapter Thirteen Exam