physics ncert solutions class 11th

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A
alok kumar singh

Contributor-Level 10

2.3 

1 Calorie = 4.2 J = 4.2 kgm2s-2

Standard formula for conversion

Given unit / New unit = (M1/M2)x (L1/L2)y (T1/T2)z

Formula for energy = M1L2T-2

Here x = 1, y = 2, z = -2

In this problem

M1 = 1 kg, L1 = 1 m, T1 = 1 s and

M2 =? kg, L2 =? m, T2 =? s

So 1 Calorie = 4.2 (1/? )1 (1/? )2 (1/? )-2

= 4.2? -1? -2? 2

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New answer posted

9 months ago

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A
alok kumar singh

Contributor-Level 10

Ans.2.1

(a) The volume of a cube of side 1 cm3 is equal to 10-6m3

The volume of the cube = 1 cm * 1 cm * 1 cm = 1 cm3

1 cm3 = 1 * 10-6 m3

(b) The surface area of a solid cylinder of radius 2.0 cm and height 10.0 cm is equal to1.25 * 104 (mm)2

The surface area of a solid cylinder = 2? r (r+)h, where r = 2.0 cm = 20 mm, h = 10 cm = 100 mmSurface area = 2 * 22/7 * 20 * (100 +20) mm2 = 1.51 * 104 mm2

(c) A vehicle moving with a speed of 18 km h–1 covers 5 m in 1 s

Vehicle speed = 18 km/h = 18000/3600 m/s = 5 m/s

(d) The relative density of lead is 11.3. Its density is 11.3 g cm–3 or 11.3 * 103.kg m–3.

Relative density or

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Rachit Kumar Saxena

Contributor-Level 9

Ans.4.1 A scalar quantity depends only on the magnitude – volume, mass, speeds, density, number of moles, angular frequency are all scalar quantities.

A vector quantity depends on magnitude and direction – velocity, acceleration, displacement and angular velocity are all vector quantities.

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