physics ncert solutions class 11th

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New answer posted

5 months ago

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V
Vishal Baghel

Contributor-Level 10

2.30

Speed of the sound in water = 1450 m s–1

Time taken from generation + reflection = 2t = 77 s

From the relation s = ut, where s is the distance of the enemy ship, we get

s = 1450 * 77/2 m = 55825 m = 55.8 km

New answer posted

5 months ago

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V
Vishal Baghel

Contributor-Level 10

2.29 Time taken by the laser beam after reflection = 2.56 s

The speed of laser = 3 * 108 m/s       

If the distance between Earth and the Moon is d, the distance covered by laser beam is 2d

From the relation distance = speed * time, we get

d = (2.56 * 3 * 108)/2 = 3.84 * 108 m

New answer posted

5 months ago

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V
Vishal Baghel

Contributor-Level 10

Kindly go through the solution

New answer posted

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V
Vishal Baghel

Contributor-Level 10

2.27

The diameter of the sodium atom = 2.5 Å = 2.5 * 10-10 m

Radius of the sodium atom = 1.25 * 10-10 m

Volume of the sodium atom = (4/3)(π) r3 = (4/3) * (22/7) * (1.25 * 10-10)  m3 = 8.18 * 10-30

Mass of 1 mole atom of sodium = 23 g = 23 * 10-3 kg

1 mole of sodium contains 6.023 * 1023 atoms.

Hence mass of 1 sodium atom = (23 * 10-3)/ (6.023 * 1023) = 3.818 * 10-26 kg

Atomic mass density of sodium = M/V = (3.818 * 10-26)/ (8.18 * 10-30) kg/m3 = 4667.48  kg/m3

The density of sodium in its solid state is 4667.48 kg/m3 but in the crystalline phase is 970 kg/m3.

In crystalline phase there are voids in between atoms, hence the density

...more

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5 months ago

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V
Vishal Baghel

Contributor-Level 10

2.26

Total time in 100 years = 100 * 365 * 24 * 60  * 60 s

Error in 100 years = 0.02 sec

Error in 1 sec= 0.02 / (100 * 365 * 24 * 60  * 60) s = 6.34 * 10-12

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5 months ago

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V
Vishal Baghel

Contributor-Level 10

2.25 In the equation v = tan(θ) , the dimension v = L1T-1. Since tan? is dimensionless, the equation v = tan(θ) is incorrect.

To make it correct v must be divided by the velocity of rain u and the correct expression should be v/u = tan(θ)

New answer posted

5 months ago

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V
Vishal Baghel

Contributor-Level 10

Kindly go through the solution

New answer posted

5 months ago

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V
Vishal Baghel

Contributor-Level 10

2.23

Mass of the Sun = 2.0 * 1030 kg

Radius of the Sun = 7.0 * 108 m

Volume of the Sun = (4/3)(π) r3 =  4/3 x(π) x (7.0 * 108)3 = 1.436 * 1027

Density of the Sun = Mass / volume = 2.0 * 1030 kg / 1.436 * 1027 kg/ m3 = 1.39 * 103 kg/ m3

The density is in the range of solids and liquids.

New answer posted

5 months ago

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V
Vishal Baghel

Contributor-Level 10

2.22

(a) During monsoons, a metrologist records about 215 cm of rainfall in India. So

Height of water column, h = 215 cm = 2.15 m

Area of the country, A = 3.3*1012 m2

Hence, volume of rain water, V = A *h = 7.09 *1012 m3

Density of water,p = 1 *103 kg/ m3

Hence, mass of rain water = p
*V
 = 7.09 *1015 kg

Hence, the total mass of rain-bearing clouds over India is approximately 7.09 *1015 kg

 

(b) Consider a ship of known base area floating in the sea.

Let the depth of the ship be d1

Volume of water displaced by the ship, Vb = A d1

Now, move an elephant on the ship and let the depth of the ship be&nbs

...more

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