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Physics Ncert Solutions Class 12th

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Physics Ncert Solutions Class 12th Class 12th

Two electrons each are fixed at a distance '2d'. A third charge proton placed at the midpoint is displaced slightly by a distance x (x << d) perpendicular to the line joining the two fixed charges. Proton will execute simple harmonic motion having angular frequency:

(m = mass of charged particle)

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Vishal Baghel

Contributor-Level 10

$F_{n e t} = \frac{2 k e e}{(d^{2} + x^{2})} s i n θ = (\frac{2 k e^{2}}{(d^{2} +^{2})}) θ$

[for small displacement i.e, x is small so|, sin $\approx$ $\approx$ tan ]

$= \frac{2 k e^{2}}{(d^{2} + x^{2})} . \frac{x}{d} = 2 . \frac{1}{4 π ε_{0}} q^{2} \frac{x}{d^{3}}$ [q = e]

$= \frac{q^{2}}{2 π ε_{0} d^{3}} x = m ω^{2} x$

$∴ ω = \sqrt[]{\frac{q^{2}}{2 π ε_{0} d^{3} m}}$

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Physics Ncert Solutions Class 12th Class 12th

Given below are two statements:

Statement I : PN junction diodes can be used to function as transistor simply by connecting two diodes, back to back, which acts as the base terminal.

Statement II : In the study of transistor, the amplification factor b indicates ratio of the collector current to the base current.

In the light of the above statements, choose the correct answer from the options given below.

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Vishal Baghel

Contributor-Level 10

A tristor is formed by doping a semi conductor water from one side by N-type dopant (high concentration while comparatively lower concentration on other side thus forming NPN tristor & vice-versa.

So, statement (I) is false & statement (II) is true.

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Physics Ncert Solutions Class 12th Class 12th

Zener breakdown occurs in a P- n junction having P and n both:

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Vishal Baghel

Contributor-Level 10

Zener break down occurs in p-n junction having p and n both : Heavily doped and have narrow depletion layer.

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Physics Ncert Solutions Class 12th Class 12th

Figure shows a circuit that contains four identical resistors with resistance R = $2.0 Ω,$ two identical inductors with inductance L = 2.0mH and an ideal battery with emf E = 9V. The current 'i' just after switch 'S' is closed will be:

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Vishal Baghel

Contributor-Level 10

R = $2 Ω$

L = 2 mH

E = 9V

$i = \frac{ε}{2 R} = \frac{9 v}{4 Ω} = 2.25 A$

Just after the switch 'S' is closed, the inductor acts as open circuit.

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Physics Ncert Solutions Class 12th Electric Flux

The electric field in a region is given by $\vec{E} = (\frac{3}{5} E_{0} \hat{i} + \frac{4}{5} E_{0} \hat{j}) \frac{N}{C} .$ The ratio of flux of reported field through the rectangular surface of are 0.2m² (parallel to y – z plane) to the of the surface of are 0.3m² (parallel to x – z plane) is a : b, where a = ……………

[Here $\hat{i}, \hat{j} a n d \hat{k}$ are the unit vectors along x, y and z – axes respectively]

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Vishal Baghel

Contributor-Level 10

$?_{1} = \frac{3}{5} E_{0} (0.2) N m^{2} C^{- 1}, a n d ?_{2} = \frac{4}{5} E_{0} (0.3) N m^{2} C^{- 1}$

$\Rightarrow \frac{?_{1}}{?_{2}} = \frac{3 * 0.2 * 5}{5 * 0.3 * 4} = \frac{1}{2}$

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Physics Ncert Solutions Class 12th Class 12th

512 identical drops of mercury are charged to a potential of 2V each. The drops are joined to form a single drop. The potential of this drop is ……………. V.

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Vishal Baghel

Contributor-Level 10

Let the charge of on each drop be q and radius of each drop be r.

$\frac{k q}{r} = 2$

When all drops are joined, radius,

$r' = {(512)}^{\frac{1}{3}} r = 8 r$

Potential of the new drop,

$V = \frac{k . 512 q}{8 r} = 64 \frac{k q}{r} = 128 V$

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Physics Ncert Solutions Class 12th Class 12th

A 5 V battery is connected across the points X and Y. Assume D₁ and D₂ to the normal silicon diodes. Find the current supplies by the battery if the +ve terminal of the battery is connected to point X.

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Vishal Baghel

Contributor-Level 10

D1 is in forward bias and D2 is in reverse bias.

Current, I $= \frac{5 - 0.7}{10} = 0.43 A$

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Physics Ncert Solutions Class 12th Communication Systems

Given below are two statements:

Statement I : A speech signal of 2 kHz is used to modulate a carrier signal of 1 MHz. The bandwidth.

Statement II : The side band frequencies are 1002 kHz and 998 kHz.

In the light of the above statements, choose the correct answer from the options given below:

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Vishal Baghel

Contributor-Level 10

Side band frequencies are 1 MHz $\pm$ 1 kHz

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Physics Ncert Solutions Class 12th Communication Systems

Given below are two statements:

Statement I : A speech signal of 2 kHz is used to modulate a carrier signal of 1 MHz. The bandwidth.

Statement II : The side band frequencies are 1002 kHz and 998 kHz.

In the light of the above statements, choose the correct answer from the options given below:

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Physics Ncert Solutions Class 12th Class 12th

Match List I with List II.

List I List II

(a) Rectifier (i) Used either for stepping up or stepping down the a.c. voltage

(b) Stabilizer (ii) Used to convert a.c. voltage into d.c. voltage

(c) Transformer (iii) Used to remove any ripple in the rectified output volt

...more

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