Physics Ncert Solutions Class 12th
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New answer posted
5 months agoContributor-Level 10
From Given equation
µ = 0.6
A? = µA?
(A? - A? )/2 = A? = 5
(A? + A? )/2 =?
A? - A? = 3
From equation (1)+ (2)
A? = 8
From equation (1)- (2)
A? = 2
New answer posted
5 months agoContributor-Level 10
Till input voltage reaches 4 V. No zener is in breakdown region. So V? = V? then now hen V? changes between 4 V to 6 V one zener with 4 V will breakdown are P.D. across this zener will become constant and remaining potential will drop acro resistance in series with 4 V zener.
Now current in circuit increases Abruptly and source must have an internal resistance due to which. Some potential will get drop across the source also so correct graph between V? and t will be
We have to assume some resistance in series with source.
New answer posted
5 months agoContributor-Level 10
A logic GATE is reversible if we can recover input data fro the output eg. NOT gate.
New answer posted
5 months agoContributor-Level 9
Magnitude of electric field is constant & the surface is equipotential.
New answer posted
5 months agoContributor-Level 10
According to Question, we can write
E = λ/ (2πε? r) ⇒ σ = ε? E = λ/ (2πr)
⇒ σ = 8*10? / (2*3.14*3) = 0.424 nCm? ²
New answer posted
5 months agoContributor-Level 10
d = √ (2hT R) + √ (2hR R) = 2√ (2hR) (assuming towers are identical)
h = d²/ (8R) = (45*10³)²/ (8*6400*10³) ≈ 39.55 m
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