Physics Ncert Solutions Class 12th
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New question posted
2 months ago
New answer posted
2 months agoContributor-Level 10
At lower end
Tension, T? = 2g = 20 N (due to the 2 kg block)
Velocity, v? = √ (T? /μ) = √ (20/μ)
Wavelength, λ? = 6 cm
At upper end
Tension, T? = (2 kg + 6 kg)g = 8g = 80 N (due to the block and the rope)
Velocity, v? = √ (T? /μ) = √ (80/μ) = √4 * √ (20/μ) = 2v?
Since frequency (f) remains the same:
f = v? /λ? = v? /λ?
⇒ λ? = λ? * (v? /v? )
⇒ λ? = λ? * (2v? /v? ) = 2λ?
⇒ λ? = 2 * 6 cm = 12 cm
New answer posted
2 months agoContributor-Level 10
From Given equation
µ = 0.6
A? = µA?
(A? - A? )/2 = A? = 5
(A? + A? )/2 =?
A? - A? = 3
From equation (1)+ (2)
A? = 8
From equation (1)- (2)
A? = 2
New answer posted
2 months ago
Contributor-Level 10
Till input voltage reaches 4 V. No zener is in breakdown region. So V? = V? then now hen V? changes between 4 V to 6 V one zener with 4 V will breakdown are P.D. across this zener will become constant and remaining potential will drop acro resistance in series with 4 V zener.
Now current in circuit increases Abruptly and source must have an internal resistance due to which. Some potential will get drop across the source also so correct graph between V? and t will be
We have to assume some resistance in series with source.
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