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Physics Ncert Solutions Class 12th

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Physics Ncert Solutions Class 12th Class 12th

A carrier wave V_C (t) = 160 sin(2p * 10⁶t) volts is made to very between V_max = 200V and V_min = 120V by a message signal V_m(t) = A_m sin(2p *10³t) volts. The peak voltage A_m of the modulating single is_________V.

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alok kumar singh

Contributor-Level 10

$μ = \frac{A_{m}}{A_{c}} = \frac{V_{1} - V_{2}}{V_{1} + V_{2}} = \frac{200 - 120}{200 + 120} = \frac{1}{4} \Rightarrow$ Modulation index

Here V_C (t) = 160 sin $(2 π * 1 0^{6} t) V a n d V_{m} (t) = A_{m} s i n (2 π * 1 0^{3} t) V, s o$

$A_{m} = \frac{A_{c}}{4} = \frac{160}{4} = 40 V$

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Physics Ncert Solutions Class 12th Class 12th

An object viewed from a near point distance of 25cm, using a microscopic lens with magnification '6', gives an unresolved image, A resolved image is observed at infinite distance with a total magnification double the earlier using an eyepiece along with the given lens and a tube of length 0.6m, if the focal length of the eyepiece is equal to_______cm.

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alok kumar singh

Contributor-Level 10

For microscopic lens

m = 1 + \frac{D}{f} \Rightarrow 6 = 1 + \frac{25}{f} \Rightarrow f = 5 c m

Now in second case, this lens acts as objective of compound microscope, so according to question

$m = m_{O} * m_{e} = \frac{L D}{f_{o} f_{e}} \Rightarrow f_{e} = \frac{L D}{m f_{o}} = \frac{60 * 25}{12 * 5} = 25 c m$

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Physics Ncert Solutions Class 12th Class 12th

A body having specific charge 8 $μ C / g$ is resting on a frictionless plane a t a distance 10cm from the wall (as shown in the figure). It starts moving towards the wall when a uniform electric field of 100 V/m is applied horizontally towards the wall. If the collision of the body with the wall is perfectly elastic, then the time period of the motion will be_________s.

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alok kumar singh

Contributor-Level 10

F = qE Þ Electric force acting on the body

$a = \frac{F}{m} = \frac{q}{m} E = \frac{8 * 1 0^{- 6}}{1 0^{- 3}} * 100 = 0.80 m / s^{2}$ ->Acceleration of body

$T = 2 \sqrt[]{\frac{2 l}{a}} = 2 \sqrt[]{\frac{2 * 0.1}{0.8}} = 1 s \Rightarrow$ Time period of Motion

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Physics Ncert Solutions Class 12th Class 12th

A capacitor is connected to a 20 V battery through a resistance of 10 $Ω .$ It is found that the potential difference across the capacitor rises to 2V in 1 $μ s .$ The capacitance of the capacitor is________ $μ F .$

Given $I n (\frac{10}{9}) = 0.105$

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alok kumar singh

Contributor-Level 10

V = 10 $(1 - e^{- t / R C})$

2 = 20 $(1 - e^{- t / R C})$

$\frac{1}{10} = 1 - e^{- t / R C}$

$e^{t / R C} = \frac{10}{9}$

$\frac{t}{R C} = l n (\frac{10}{9}) = 0.105$

$C = \frac{t}{R * 0.105} = \frac{1 0^{- 6}}{10 * 0.105} = 0.95 μ F$

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Physics Ncert Solutions Class 12th Class 12th

A glass tumbler having inner depth of 17.5cm is kept on a table. A student starts pouring water $(μ = 4 / 3)$ into it while looking at the surface of water from the above. When he feels that the tumbler is half filled, he stops pouring water. Up to what height, the tumbler is actually filled?

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alok kumar singh

Contributor-Level 10

As observer is at O So height of water observed by observer

$\Rightarrow \frac{H}{μ_{ω}} = \frac{H}{(4 / 3)} = \frac{3 H}{4}$

given diagram (17.5 - H) is height of observer

$S o \frac{3 H}{4} = 17.5 - H$

$\frac{7 H}{4} = 17.5$

7H = 70

H = 10

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Physics Ncert Solutions Class 12th Class 12th

In the given figure, each diode has a forward bias resistance of 30 $Ω$ and infinite resistance in reverse bias. The current I₁ will be:

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alok kumar singh

Contributor-Level 10

In give diagram Diode 1 and 2 are in forward bias with R = $30 Ω$ and Diode 3 is reverse bias with R = infinite l₁ current is flowing through 20 $Ω$

So $\frac{l_{1}}{2} a n d \frac{l_{1}}{2}$ current will flow through Diode 1 and 2. As resistance is same applying KCl in ABCD Loop $- \frac{l_{1}}{2} * 130 - \frac{l_{1}}{2} * 130 - l_{1} * 20 + 200 = 0$

-100l₁ + 200 = 0

l₁ = 2

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Physics Ncert Solutions Class 12th Class 12th

A carrier wave with amplitude of 250 V is amplitude modulated by a sinusoidal base band signal of amplitude 150V. The ratio of minimum amplitude to maximum amplitude for the amplitude modulated wave is 50 : x, then value of x is__________.

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alok kumar singh

Contributor-Level 10

$A_{m a x} = A_{c} + A_{m}$

$A_{m i n} = A_{c} - A_{m}$

$\frac{A_{m i n}}{A_{m a x}} = \frac{A_{c} - A_{m}}{A_{c} + A_{m}} = \frac{250 - 150}{250 + 150}$

$\Rightarrow \frac{100}{400} = \frac{50}{200}$

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2 months ago

Physics Ncert Solutions Class 12th Class 12th

A parallel plate capacitor of capacitance 200 $μ F$ is connected to a battery of 200V. A dielectric slab of dielectric constant 2 is now inserted into the space between plates of capacitor while the battery remain connected. The change in the electrostatic energy in the capacitor will be_______J.

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Vishal Baghel

Contributor-Level 10

Battery is connected while dielectric is inserted so potential difference will be remains same.

$U_{i} = \frac{1}{2} c V^{2}$

$U_{f} = \frac{1}{2} K c V^{2}$

$\Rightarrow Δ U = \frac{1}{2} (K - 1) c V^{2} = \frac{1}{2} * 1 * 200 * 1 0^{- 9} * 20 0^{2} = 4$

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Physics Ncert Solutions Class 12th Communication Systems

A bandwidth of 6 MHz is available for A.M. transmission. If the maximum audio signal frequency used for modulating the carrier wave is not to exceed 6 kHz. The number of stations that can be broadcasted within this band simultaneously without interfering with each other will be_______.

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Vishal Baghel

Contributor-Level 10

Signal bandwidth = 12KHz

No. of station = $\frac{6 M H z}{12 k H z} = 500$

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Physics Ncert Solutions Class 12th Class 12th

Statement-I : To get a steady dc output from the pulsating voltage received from a full wave rectifier we can connect a capacitor across the output parallel to the load RL.

Statement-II : To get a steady dc output from the pulsating voltage received from a full wave rectifier we can connect an inductor in series with RL.

In the light of the above statements, choose the most appropriate answer from the options given below:

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Vishal Baghel

Contributor-Level 10

Capacitor makes potential difference constant.

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