Physics Ncert Solutions Class 12th

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New answer posted

2 months ago

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V
Vishal Baghel

Contributor-Level 10

Assuming shell to be conducting

For  0 r < R q i n = 0 ,

E = 0

R r < a q i n = Q       

E = k Q r 2            

a r < b q i n = Q Q = 0          

E = 0

r b q i n = Q

E = k Q r 2

New answer posted

2 months ago

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V
Vishal Baghel

Contributor-Level 10

Optical fibre frequency range is 1 THz to 1000 THz.

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2 months ago

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V
Vishal Baghel

Contributor-Level 10

Very small change in minority charge carriers produces high value of reverse bias current.

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A
alok kumar singh

Contributor-Level 10

Y ->And gate

A

B

Y

0

0

0

1

1

1

0

1

0

1

0

0

 

New answer posted

2 months ago

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A
alok kumar singh

Contributor-Level 10

F R = { k Q q 0 ( a x ) 2 k Q q 0 ( a + x ) 2 }

= k Q q 0 { a 2 + x 2 + 2 a x a 2 x 2 + 2 a x ( a 2 x 2 ) }

F R = k Q q 0 ( 4 a x ) ( a 2 x 2 ) 2

T = 2 π a 3 m 4 k Q q 0 = 4 π 2 a 3 m * 4 π ε 0 4 Q q 0 = 4 π 3 ε 0 m a 3 Q q 0 .                          

   

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A
alok kumar singh

Contributor-Level 10

Voltage gain = I C R 0 I B R i  

R0 ->Output Resistance

Ri ->Input Resistance

IC ->Collector current

IB ->Base current

Voltage gain = I C I B R 0 R i = ( 5 * 1 0 3 ) ( 1 0 0 * 1 0 6 ) * 6 0 2 0 0 = 1 5  

New answer posted

2 months ago

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A
alok kumar singh

Contributor-Level 10

Kindly go through the solution

Based on theory

New answer posted

2 months ago

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A
alok kumar singh

Contributor-Level 10

Kindly go through the solution

 

New answer posted

2 months ago

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A
alok kumar singh

Contributor-Level 10

  B = η μ 0 l

 if l ->2l

η n 2                

B 1 = n 2 μ 0 2 l

B 1 = B                

               

New answer posted

2 months ago

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P
Payal Gupta

Contributor-Level 10

I=I0cos230°

=I0 (32)2=34I0 

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