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New answer posted

5 months ago

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V
Vishal Baghel

Contributor-Level 10

  p 1 p 2 = 4 T r 1 . . . . . . . ( 1 )

p 2 p 0 = 4 T r 2 . . . . . . . ( 2 )

(1) + (2), p1 – p0 = 4T ( 1 r 1 + 1 r 2 )

4 T r e q = 4 T ( 1 r 1 + 1 r 2 )

r e g = r 1 r 2 r 1 + r 2 = 3 * 6 3 + 6 = 2 c m

             


New answer posted

5 months ago

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A
alok kumar singh

Contributor-Level 10

L e t , E m a g b T c

So, [ E ] = [ m ] a [ g ] b [ T ] c  

M L 2 T 2 = M a ( L T 2 ) b T c  

Thus, E = k mg2 T2

Δ E E = 2 . Δ g g + 2 . Δ T T   

Percentage error in E = 2 * 4 + 2 * 3 = 14%

New answer posted

5 months ago

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V
Vishal Baghel

Contributor-Level 10

For first fringe

d y 1 D = 1 * λ 1 [ n = 1 ] λ 1 Red wavelength

d y 2 D = 1 * λ 2 [ n = 1 ] λ 2 violet wavelength

d D ( y 1 y 2 ) = λ 1 λ 2           

y 1 y 2 = D d ( λ 1 λ 2 )        

= 0 . 3 * 1 0 3 1 . 5 ( 3 . 5 2 ) * 1 0 3

= 300 * 10-9

= 300 nm

New answer posted

5 months ago

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A
alok kumar singh

Contributor-Level 10

2nqV = 1 2 m v 2

n = m v 2 4 q V

= 1 . 6 7 * 1 0 2 7 * ( 0 . 5 * 1 0 8 ) 2 4 * 1 . 6 * 1 0 1 9 * 1 2 * 1 0 3 = 5 4 3  

             

New answer posted

5 months ago

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V
Vishal Baghel

Contributor-Level 10

  τ 2 = B 1 M 2 S m 9 0 °

= B1 M2

= ( μ 0 4 π * m 1 r 3 ) * m 2        

= 1 0 7 1 1 3 * 1

= 10-7 N – m

New answer posted

5 months ago

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A
alok kumar singh

Contributor-Level 10

l 2 c o s 2 ? = 3 l 8

? c o s ? = 3 2

? ? = 3 0 °

New answer posted

5 months ago

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A
alok kumar singh

Contributor-Level 10

Kindly go through the solution 

  F m a x 1 + 2 = 0 . 5 * 1 0 F m a x = 1 5 N

New answer posted

5 months ago

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V
Vishal Baghel

Contributor-Level 10

= l x x ' = [ l y y ' + M ( 5 r 2 ) 2 ] + [ l Z Z ' + M ( 1 3 r 2 ) 2 ]

M ( 3 6 r 2 1 2 ) + M * 2 5 r 2 4 = M r 2 2 + M * 1 6 9 M r 2 4

= 52 Mr2

New answer posted

5 months ago

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A
alok kumar singh

Contributor-Level 10

msx (16 – 10) = msy (20 – 16)

  s x s y = 2 3             

m s y ( 2 6 2 0 ) = m s z ( 3 0 2 6 )               

  s y s z = 2 3             

s x s z = s x s y * s y s z = 2 3 * 2 3 = 4 9              

  m s x ( T 1 0 ) = m s z ( 3 0 T )            

->4(T – 10) = 9(30 – T)

->T = 23.84°C

 

New answer posted

5 months ago

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V
Vishal Baghel

Contributor-Level 10

f ' = 3 4 0 2 0 3 4 0 + 2 0 * f 0

1 8 0 0 = 3 2 0 3 6 0 * f 0

f0 = 2025 Hz

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