Physics

Get insights from 5.6k questions on Physics, answered by students, alumni, and experts. You may also ask and answer any question you like about Physics

Follow Ask Question
5.6k

Questions

0

Discussions

29

Active Users

0

Followers

New answer posted

5 months ago

0 Follower 3 Views

P
Payal Gupta

Contributor-Level 10

m1=900gm, w1=k.9

m2=1024gm, ω2=k1.024

m1v1=m2V2

m1ω1A1=m2ω2A2

A1A2=1024900=3230=1615=16161

New answer posted

5 months ago

0 Follower 2 Views

P
Payal Gupta

Contributor-Level 10

x=2ε0ρ

E2πxl=ρπx2lε0

Ex=ρx22xε0=ρx2ε0

=ρ2ε0*2ε0ρ=1v/m

New answer posted

5 months ago

0 Follower 8 Views

P
Payal Gupta

Contributor-Level 10

i = 1 A j=σE

A = 2mm2

ρ=1.7*108Ωm F=eE=ejσ=eiAσ=eiρA

1.6*1019*1.7*1082*106

= 136 * 10-23 N

New answer posted

5 months ago

0 Follower 2 Views

P
Payal Gupta

Contributor-Level 10

R=v2P=1000050R=200Ω

V=VC2+VR2

200=VC2+ (100)2

xc=1ωc=πx100π*50=x5000*106=x*1035

=200x

VC=ixC

3.1+x=2x

3 (1+x)=4xx=3

New answer posted

5 months ago

0 Follower 2 Views

P
Payal Gupta

Contributor-Level 10

 ? A=π2, ? B=π3

IA=I1+I2+2l1l2cos? =l+4l+2l*4lcosπ2=5l

IB=I+4I+2l.4lcosπ3=5l+2l=7l

Δl=7l5l=2lx=2

New answer posted

5 months ago

0 Follower 1 View

P
Payal Gupta

Contributor-Level 10

1 msD = 1mm

10 vsD = 9msD

1vsD = 0.9 MsD

L.C. = 1MSD – 1VSD = 1 – 0.9 = 0.1 mm

Zero error = 4LC = 0.4 mm

Reading = MSR + VSR + correction

= 4.1 cm + 6 * .01 cm + (-0.04 cm) = (4.1 + 0.06 – 0.04) cm

= 4.12 cm = 412 * 10-2 cm

New answer posted

5 months ago

0 Follower 4 Views

P
Payal Gupta

Contributor-Level 10

3070=S5.6kΩS=37*5.6kΩ=3*0.8kΩ

= 2.4k Ω = 2400 Ω

New answer posted

5 months ago

0 Follower 8 Views

B
Baskaran M

Contributor-Level 9

Math calculation is important for BiPC students as it is used in:

1. Physics and chemistry problem-solving

2. Biology for statistical analysis and modeling

3. Medical and health sciences

4. Research and data analysis

Basic math skills can benefit BiPC students in their academic and professional pursuits.

New answer posted

5 months ago

0 Follower 2 Views

P
Payal Gupta

Contributor-Level 10

ein=|d? dt|=|16t9|ein=|16*149|=5volt

l=einR=520A=520*1000mA=250mA

New answer posted

5 months ago

0 Follower 4 Views

P
Payal Gupta

Contributor-Level 10

For refraction of light at lens

1v160=120

1v=1201601v=3160=130

v = 30 cm

If image has to be formed at object itself then light ray should retrace its path. Hence after refraction at lens, it must strikes normally to the mirror

RM = 20 cm Radius of curvature of mirror

Fm = 10 cm focal length of mirror

Get authentic answers from experts, students and alumni that you won't find anywhere else

Sign Up on Shiksha

On Shiksha, get access to

  • 66k Colleges
  • 1.2k Exams
  • 681k Reviews
  • 1800k Answers

Share Your College Life Experience

×
×

This website uses Cookies and related technologies for the site to function correctly and securely, improve & personalise your browsing experience, analyse traffic, and support our marketing efforts and serve the Core Purpose. By continuing to browse the site, you agree to Privacy Policy and Cookie Policy.