Physics

Water level in both section A and B will be goes up due being of centrifugal force water will goes away and it acquire the force from upside so the water will does up so water level in both the section A and B goes up.

By given $U=54joulem=3kg$

By conservation of mechanical energy law

$\left(K+U\right)$ Earth surface $=\left(K+U\right)\infty$

$\frac{1}{2}m{v}^2+\left(-54J\right)=0+0$

$\frac{1}{2}m{v}^2=54$

$3v^2=108$

$v^2=\frac{108}{3}=36$

v= 6m/s

$As{V}^2=V_R^2+C_C^2$

$?V_R=\sqrt[]{V^2-V_C^2}=\sqrt[]{{10}^2-8^2}=6V$

$\tan ?\theta =\frac{X_C}{X_R}=\frac{V_C}{V_R}=\frac{8}{6}=\frac{4}{3}$

R =? *L/A

This is the formula of calculating a wire's resistance. If you look closely at the formula,

A= cross sectional area

More the surface area, more will be the area for passage of free electrons.

Hence, we can easily conclude that thickness of a wire plays an jmportant role in determining it's conductivity.

From first law of thermodynamics

$?W=?Q-?U$

$?Q=n{C}_p?T$

$?U=n{C}_v?T$

$?W=n(C_p-C_v)?T$

$\frac{?Q}{?W}=\frac{\gamma }{\gamma -1}\left. [\frac{C_p}{C_p}=\gamma \right]$

This happens due to the lack of electrons. Metals have a solid flow of electric current in their bodies due to the presence of free electrons moving throughout. These electrons are responsible for carrying electric charges which makes them a good conductor of electricity. however, the lack of these electrons in non-metals makes them an insulator.

From F.B. Ds of

$9kg\to 90-T_1=9a\dots .\left(1\right)$

$6kg\to T_1-T_2=6a\dots ..\left(2\right)$

$5kg\to T_2-50=5a\dots ..\left(3\right)$

$\left(1\right)+\left(2\right)+\left(3\right)$

$40=20a?a=2m/s^2$

For minima

$d\cos ?\theta =\left(n+\frac{1}{2}\right)\lambda$

$?\cos ?\theta =\frac{2n+1}{8}$

$?n=-4,-3,-2,-1,0,1,2,3$

$?8$ minimas