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Physics Class 11th

An observer moves towards a stationary source of sound with a velocity one-fourth of the velocity of sound. What is the percentage increase in the apparent frequency?

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Vishal Baghel

Contributor-Level 10

$f' = f ⌊ \frac{v + \frac{v}{4}}{v} ⌋ = \frac{5 f}{4}$

$\Rightarrow \frac{f'}{f} = \frac{5}{4}$

$\Rightarrow \frac{Δ f}{f} = \frac{1}{4}$

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New answer posted

2 months ago

Physics Physics Thermodynamics

A Carnot engine working between the temperature 500 K and 1000 K does a work of 1000 J. The heat energy supplied by the source to the engine per cycle is

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Vishal Baghel

Contributor-Level 10

$η = 1 - \frac{T_{2}}{T_{1}} = 1 - \frac{500}{1000} = \frac{1}{2}$

$η = \frac{W}{Q_{1}}$

$\Rightarrow Q_{1} = \frac{W}{η} = \frac{1000}{1 / 2}$

$\Rightarrow Q_{1} = 2000 J$

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2 months ago

Physics Physics Thermodynamics

Consider a process on a system shown in figure below. During the process, the work done by the system

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Vishal Baghel

Contributor-Level 10

During the process are under P – V graph continuously increases but rate of increment varies.

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2 months ago

Physics Physics Mechanical Properties of Fluids

A rain drop of radius r falls in air with terminal velocity v. What is the terminal velocity of a rain drop of radius 3r?

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Vishal Baghel

Contributor-Level 10

$v_{T} \propto r^{2}$

$\frac{v_{T_{1}}}{v_{T_{2}}} = \frac{r_{1}^{2}}{r_{2}^{2}} = \frac{r^{2}}{9 r^{2}}$

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2 months ago

Physics Physics System of Particles and Rotational Motion

Two circular rings (of same material) are of same thickness. The diameter of first ring is twice that of second. The moment of inertia of first ring as compared to that of second is

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Vishal Baghel

Contributor-Level 10

$\frac{l_{1}}{l_{2}} = \frac{M_{1} R_{1}^{2}}{M_{2} R_{2}^{2}} = \frac{ρ * 2 π R_{1} * R_{1}^{2}}{ρ * 2 π R_{2} * R_{2}^{2}} = \frac{R_{1}^{3}}{R_{2}^{3}} = \frac{8}{1}$

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New answer posted

2 months ago

Physics Physics System of Particles and Rotational Motion

In rotational motion of a rigid body about an axis, particles move with

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Vishal Baghel

Contributor-Level 10

In rotational motion, angular velocity of every particle on rigid body will be same. But linear velocity is given as v = $r ω .$

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2 months ago

Physics Physics System of Particles and Rotational Motion

A body of moment of inertia 4 kg m2 rotating with an angular speed of 4 rad/s has the 4x J of kinetic energy. Determine the value of x.

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Vishal Baghel

Contributor-Level 10

$K . E = \frac{1}{2} l ω^{2}$

$K . E = \frac{1}{2} * 4 * 16 = 32 = 4 * 8 J$

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2 months ago

Physics Class 11th

An insect of mass m = 2g is inside a vertical drum of radius 1m that is rotating with an angular velocity of 10 rad/s. If the insect does not fall off then the minimum coefficient of friction is

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Vishal Baghel

Contributor-Level 10

$f ? m g$

$? ? m r ?^{2} ? m g$

$? ? = \frac{g}{r ?^{2}} = \frac{10}{1 * 100} = 0.1$

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2 months ago

Physics Class 11th

A particle moves in a circular orbit of radius r under a central attractive force F = $- \frac{k}{r},$ k is constant. The time period of its motion is proportional to

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Vishal Baghel

Contributor-Level 10

$F = m r ω^{2} = \frac{k}{r}$

$\begin{array}{l} \Rightarrow ω \propto \frac{1}{r} \\ \Rightarrow T \propto r \end{array}$

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2 months ago

Physics Work, Energy and Power

The position x of a particle of mass 2kg moving along straight line is given as x = (t – 2)², where t is in second and x is in metre. The work done by the force in first 2s is

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Vishal Baghel

Contributor-Level 10

$\begin{array}{l} \Rightarrow x = {(t - 2)}^{2} \\ \Rightarrow v = 2 t - 4 \end{array}$

$v_{t = 0} = - 4 m / s$

$v_{t = 2} = 0 m / s$

Work done $= Δ K$

$\Rightarrow W = \frac{1}{2} m * 0 - \frac{1}{2} * 2 * 16$

=> W = 16 J

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