Application of Integrals

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New answer posted

4 months ago

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V
Vishal Baghel

Contributor-Level 10

Kindly go through the solution

[ x 3 2 3 2 ] 0 a = [ x 3 2 3 2 ] a 2 3 [ a 3 2 0 ] = 2 3 [ 4 3 2 a 3 2 ] a 3 2 = 4 3 2 a 3 2 2 a 3 2 = 4 3 2
 

4a3=43 (Squaring both sides)

a3=42

a=423 (Taking cube on both sides)

New answer posted

4 months ago

0 Follower 1 View

V
Vishal Baghel

Contributor-Level 10

Kindly go through the solution

New question posted

4 months ago

0 Follower 4 Views

New answer posted

4 months ago

0 Follower 1 View

V
Vishal Baghel

Contributor-Level 10

Kindly go through the solution

New answer posted

4 months ago

0 Follower 1 View

V
Vishal Baghel

Contributor-Level 10

Kindly go through the solution

New answer posted

4 months ago

0 Follower 1 View

V
Vishal Baghel

Contributor-Level 10

Kindly go through the solution

New answer posted

4 months ago

0 Follower 7 Views

V
Vishal Baghel

Contributor-Level 10

Kindly go through the solution

New answer posted

4 months ago

0 Follower 1 View

V
Vishal Baghel

Contributor-Level 10

Kindly go through the solution

New answer posted

4 months ago

0 Follower 1 View

V
Vishal Baghel

Contributor-Level 10

Kindly go through the solution

New question posted

4 months ago

0 Follower 1 View

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