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New answer posted

a month ago

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V
Vishal Baghel

Contributor-Level 10

Velocity of an electron in the nth orbit:

v ∝ 1/n

New answer posted

a month ago

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V
Vishal Baghel

Contributor-Level 10

E_ground (H-atom) = -13.6 eV

E_carbon = E_ground (H-atom) * Z²/n²
For carbon, Z=6.

-13.6 eV = -13.6 eV * (6²/n²)

1 = 36/n²

n² = 36

n = 6

New answer posted

a month ago

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A
alok kumar singh

Contributor-Level 10

M? = 200MeV/C², m = 1Gev/C²
Initial velocity of particle is 'V'.
Final velocity of hydrogen atom is 'V'
M? V? = mV
V = M? V? /m
Also, 1/2 M? V? ² = 1/2 mV² + 3/4 x 13.6
Put (1) and get answer
1/2 M? V? ² = 51/4 eV
Hence, N = 51.

New answer posted

a month ago

0 Follower 3 Views

V
Vishal Baghel

Contributor-Level 10

Binding energy = (50M? + 70M? – Msn)C²
= (50.3915 + 70.6069 – 119.902199)U²
= (1.0962U)C²
= 931 * 1.0962MeV

Binding energy per neucleon
= (931 x 1.0962)/120 MeV
= 8.5MeV

New answer posted

a month ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

Sol. eVslop = hc/λ - φ

Slope of curve

tan θ = hc/e = constant
as intensity of incident radiation is increased, there will be no effect on graph

New answer posted

a month ago

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A
alok kumar singh

Contributor-Level 10

1/λmin = R [1/1² - 1/∞²] = R [n=∞ → n=1]
1/λmax = R [1/1² - 1/2²] = 3R/4 [n=2 → n=1]
⇒ Δλ ⇒ 4/3R - 1/R ⇒ 1/3R ⇒ 340
For Paschan ⇒ 1/λmin = R [1/9] [n=∞ → h=3]
⇒ 1/λmax = R [1/9 - 1/16] = 7R/144
⇒ Δλ = 81/7R

New answer posted

a month ago

0 Follower 4 Views

A
alok kumar singh

Contributor-Level 10

Density = M V = 1.67 * 10 - 27 * A 4 3 π ( 1.3 ) 3 * 10 - 45 * A 10 17

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