B.E. Eligibility

To be eligible for B.E / B.Tech course at V College of engineering, students need to have passed 12th with a minimum of 45% aggregate or decent score in entrance exam TNEA followed by the TNEA councelling process which is conducted online.

To be eligible to take admission in JP College Of Engineering you need to pass 12th with 45% aggregate and the accepting entrance exam TNEA. The college offers BE? BTECH course in 7 specialisations . Admission is based on the merit scores achieved by candidates in the last exam be it 12th or TNEA. After the entrance exam, admission will be alloted through councelling process.

For B.E./B.Tech at Renganayagi Varatharaj College of Engineering, candidates must have completed their 10+2 (or equivalent) in the Science stream with Physics, Chemistry, and Mathematics as core subjects. They need a minimum aggregate score of 50% in these subjects (45% for BC/BCM, 40% for MBC/DNC, and mere pass for SC/SCA/ST). Admission is primarily based on a valid score in the TNEA (Tamil Nadu Engineering Admissions) or other recognised national-level engineering entrance exams.

The selection criteria for the B.E./B.Tech courses at Drs. Kiran and Pallavi Patel Global University (KPGU) have a combination of merit and entrance exam scores.
For Gujarat State Board students, a merit list is prepared with 60% weightage given to 11th and 12th-grade scores and 40% to GUJCET scores.

 For students from other state boards, the criteria shifts to 60% weightage for 12th-grade scores and 40% for GUJCET. And some seats are allocated based on JEE Main scores for All India category students.

B.E. / B.Tech in IES College of technology requires that the candidate should have qualified the 10+2 (Higher Secondary) with Physics, Chemistry, and Mathematics as subjects compulsory. There should be a minimum mark of 45 % in aggregate (40 % in reserved categories). The admissions are majorly conducted based on the scores of JEE Main and then ahead counseling of MP BE. Lateral entrance into the second year is feasible to Diploma holder in Engineering, or B.Sc. graduates with Mathematics, on comparable percentage terms.

The eligibility criteria to get admission in BTech is to pass 10+2 with 45% + UPTAC. The total tuition fee for BTech (2025) is INR 3.07 Lakhs.

B.Tech. in Computer Science and Engineering at Feroze Gandhi Institute of Engineering and Technology is a 4 years course offered in a Full Time mode.