B.E.
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3 years agoBeginner-Level 4
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3 years agoBeginner-Level 5
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3 years ago
Contributor-Level 6
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3 years agoContributor-Level 10
1. Candidates first have to meet the eligibility criteria.
2. After that, candidates have to register on the TNEA website.
3. A merit list will be prepared based on the scores of Mathematics, Physics and Chemistry obtained in class 10+2.
4. Based on merit, ranks will be generated.
5. Candidates whose names are on the rank list have to appear for TNEA online counselling.
6. Seats will be
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3 years agoGuide-Level 15
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3 years ago
Scholar-Level 16
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3 years agoBeginner-Level 5
Here is the general category's home state and other states ranks, respectively.
NIT TRICHY- 8128, 3022
NIT Warangal- 4689, 4671
NIT Suratkal- 8383, 4151
NIT Allahabad-8622, 7138
NIT ROURKELLA- 13002, 5059
New answer posted
3 years agoContributor-Level 6
The eligibility to appear in NEET (UG) is as per the respective regulations: As per nationality - Indian, Persons of Indian Origin, Overseas Citizens of India, Foreign Nationals and Non-resident Indians are eligible to appear in NEET-UG exam
Only students having qualification recognised as equivalent by the Association Of Indian Universities (AIU) are only eligible for a
New answer posted
3 years agoBeginner-Level 4
The previous year's cutoff for the General category for B.E. in Computer Science and Engineering at Chandigarh College of Engineering and Technology was around 94-95 marks out of 200 in the Joint Entrance Exam (JEE) Main. However, the cutoff varies each year depending on the factors mentioned above.
It is important to note that cutoffs are
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