B.Tech Eligibility
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New answer posted
11 months agoContributor-Level 8
The eligibility criteria for admission to B.E. / B.Tech courses of SACS MAVMM Engineering College include:
Qualification: Candidates should have 10+2 (Higher Secondary) qualification from any recognised board with Physics, Chemistry, and Mathematics as core subjects.
Minimum Marks: Aggregate of 50% (45% for the reserved categories) from the qualifying exam.
Entrance Test: For entrance, the candidate will be considered on the basis of performance in TNEA (Tamil Nadu Engineering Admissions) or other State/ National Level Entrance tests.
Age Bar: Candidates must be at least 17 years of age at the date of admission.
New answer posted
11 months agoContributor-Level 8
RVS College of Engineering and Technology Admission Eligibility Criteria of B.E. / B.Tech
Candidate should have passed 10+2 (or equivalent) with Physics, Chemistry, and Maths as compulsory subjects for B.E. / B.Tech.
Minimum Marks: The minimum aggregate marks in the qualifying examination will be 50% or above (45% in case of reserved categories).
Entrance Exam Admission through entrance test TNEA Tamil Nadu Engineering Admissions, or entrance exams conducted at state levels Other State students can also apply under Management Quota or JEE Main score.
Age Requirement: A candidate is to be at least 17 years of age during the admission year.
New answer posted
11 months agoContributor-Level 8
Eligitibilty criteria for B.E. / B.Tech Admissions: All candidates who seek admission in B.E. / B.Tech courses under Rural Engineering College may apply if they have passed 10 + 2 examination or equivalent from a recognised board in which he/she must have Physics, Chemistry and Math's as compulsory subjects.
Minimum Marks: 50% aggregate marks (45% in case of reserved categories).
Entrance Exam: Admission usually takes place based on marks obtained in entrance examination conducted at the state level, such as MHT CET or national level exams, like JEE Main.
Minimum Age: The candidate should have completed at least 17 years of age by the end
New answer posted
11 months agoContributor-Level 9
Here's the eligibility criteria for B.E./B.Tech at Sri Venkatesa Perumal College of Engineering and Technology (SVPCET):
Eligibility Criteria:
1. Qualifying Exam: Intermediate (10+2) or its equivalent.
2. Optional Subjects: Mathematics, Physics and Chemistry.
3. Entrance Exam: Engineering, Agriculture and Pharmacy Common Entrance Test (EAPCET).
Minimum Requirements:
1. Minimum Marks: In the qualifying exam he/she should obtain at least fifty percent marks.
2. Age: No upper age limit.
Additional Requirements:
1. EAPCET rank.
2. Certificate verification.
Reservation:
1. SC/ST: 15% and 7.5% reservation.
2. BC: 25% reservation.
Please be informed to che
New answer posted
11 months agoContributor-Level 10
The eligibility criteria for B.E. / B.Tech at Kshatriya College of Engineering (KCEA) are:
- Educational Qualification: Completion of 10+2 with at least 45% marks (40% for SC/ST) in Physics, Chemistry, and Mathematics (PCM).
- Entrance Exam: Candidates must qualify for TS EAMCET or another relevant entrance exam.
- Age Limit: Minimum age of 16 years and maximum age of 22 years (general) or 24 years (SC/ST).
- Domicile: Preference is given to Telangana residents, though out-of-state candidates can also apply.
New answer posted
11 months agoContributor-Level 10
To be eligible for B.E./B.Tech at Lukhdhirji Engineering College (LEC), candidates must:
- Complete 10+2 with Physics, Chemistry, and Mathematics (PCM).
- Minimum Marks: Typically, a minimum of 45% in 10+2 (40% for reserved categories) is required.
- Entrance Exam: Candidates must appear for and qualify in GUJCET (Gujarat Common Entrance Test) or JEE Main for admission.
For more details, you can visit LEC's official website or refer to the admission guidelines by the Admission Committee for Professional Courses (ACPC).
New answer posted
11 months agoContributor-Level 10
Eligibility for admission in B.E./B.Tech at Shri Dharmasthala Manjunatheshwara College of Engineering and Technology is: 45% aggregate in 10+2 with Physics, Mathematics, and Chemistry/Biotechnology/Biology. Candidates must have an appearance in the KCET/COMEDK/JEE Main exams. The minimum ranks required for admission into the college are: KCET - rank between 50,000-70,000, COMEDK - rank between 50,000-80,000, JEE Main - rank between 50,000-100,000. Admissions are made on lateral entry basis to the 2nd year with 45% in 3-year Diploma or equivalent with Mathematics. Reservation is made based on government guidelines. Total intake is for 8
New answer posted
11 months agoContributor-Level 10
For B.E./B.Tech at Scient Institute of Technology, the requirements are: 10+2 with 45% aggregate in Physics, Mathematics and Chemistry/Biotechnology/Biology. Candidates should appear for TS EAMCET/JEE Main. Cutoff ranks: TS EAMCET: 10,000-20,000, JEE Mains: 50,000-100,000. Lateral Entry for Diploma holders (60% aggregate). Reservation: 85% for Telangana students, 15% others. Seats: 600 CE-120, EEE-120, ECE-120, ME-120, CSE-120. Application fee: INR 1,000. Admission timeline: May-July every year.
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