Chemical Equilibrium

When nucleoside is linked to phosphoric acid at 5 '-position of sugar moiety, we get nucleotide.

| List-I | | List-II |
| :- | :- | :- |
| (a) 2SO? (g) + O? (g) → 2SO? (g) | (iv) | Tropospheric pollution |
| (b) HOCl (g) - (hν)->? H +? l | (iii) | Ozone depletion |
| (c) CaCO? + H? SO? → | (i) CaSO? + H? O + CO? | Acid rain |
| (d) NO? (g) - (hν)-> NO (g) + O (g) | (ii) | Smog |

(Pent-2-ene)

(Major product by Saytzeff's rule)

3O? 2O?                                                                                                                                                  

pH = pK? + log ( [CH? COONa] / [CH? COOH])
pH = 4.57 + log (0.1 / 0.01) = 5.57

ΔG° = -9.478 kJ/mol
Using ΔG° = -2.303 RT log K_p
-9.478 * 10³ = -2.303 * 8.314 * 495 log K_p
1 = log K_p ⇒ K_p = 10
Here, for the given reaction A (g)? B (g), K_p = K_c
Initial A = 22 mmol
At equilibrium A = 22 - x mmol; B = x mmol
K_c = [B] / [A] = (x/V) / (22-x)/V) = x / (22-x) = 10
x = 10 (22-x) ⇒ x = 220 - 10x ⇒ 11x = 220 ⇒ x = 20
So, mmol of B at equilibrium are 20.

Sucralose: Artificial sweetener

Glyceryl ester of stearic acid: The document incorrectly identifies this as "Sodium stearate which is synthetic detergent". Sodium stearate is a soap, not a synthetic detergent.

Sodium benzoate: Food preservative

Bithionol: Antiseptic

Please consider the following Image

For the coagulation of a negative sol, the species Ba²? has the highest flocculating power (referring to the Hardy-Schulze rule, where higher charge leads to greater coagulation power).