Chemical Equilibrium

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3 months ago

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R
Raj Pandey

Contributor-Level 9

Matching Processes with Catalysts:

o   (a) Deacon's process: CuCl? used as catalyst

o   (b) Contact process: V? O? used as catalyst

o   (c) Cracking of hydrocarbon: ZSM-5 used as catalyst

o   (d) Hydrogenation of vegetable oil: Particles Ni used as catalyst

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A
alok kumar singh

Contributor-Level 10

In endothermic reaction formation of reactants is favoured upon decrease in temperature. Addition of inert gas at constant volume and temperature has no effect on equilibrium.

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A
alok kumar singh

Contributor-Level 10

(x/m) = k (P)¹/?
log (x/m) = log k + (1/n) log P
Slope = 1/n = 2 So n = ½
Intercept ⇒ log k = 0.477 So k = Antilog (0.477) = 3
So (x/m) = k (P)¹/? = 3 [0.04]² = 48 * 10?

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V
Vishal Baghel

Contributor-Level 10

On adding reaction equilibrium constant will get multiplied.

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Raj Pandey

Contributor-Level 9

At equilibrium rate of forward and backward reaction becomes equal.

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A
alok kumar singh

Contributor-Level 10

Asp - Glu - Lys pripeptide is:

No. of C O group = 5

 

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A
alok kumar singh

Contributor-Level 10

(b) It is harmful for trees and plants

(c) It causes breathing problem in human being and animals

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