Equilibrium
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0.01 M NaOH,
M = 1 * 10-2

pOH = 2
pH = 2
Kp for the given reaction is (36 × 10–2atm–1) Find out Kc (M–1) (nearest integer).
(2NO2 N2O4)
(R=0.0821 atm. L/mol. K)
(T = 300K)
Kp for the given reaction is (36 × 10–2atm–1) Find out Kc (M–1) (nearest integer).
(2NO2 N2O4)
(R=0.0821 atm. L/mol. K)
(T = 300K)
Kp = Kc (RT)Dng
36 * 10–2 = Kc (0.0821 * 300)–1
Kc = 0.36 * 0.0821 * 300 = 8.86 » 9
A(g) ->B(g) + <!-- [if gte mso 9]><xml>
</xml><![endif]-->C(g)
In the about reaction, the correct relation between Kp, a and equilibrium pressure (p) is
A(g) ->B(g) + <!-- [if gte mso 9]><xml>
In the about reaction, the correct relation between Kp, a and equilibrium pressure (p) is
A(g) ->B(g) + (g)
Initial moles n 0 &nbs
Which of the following equilibrium will shift in forward direction on applying pressure?
Which of the following equilibrium will shift in forward direction on applying pressure?
On increasing pressure, equilibrium moves in that direction where number of gaseous moles decreases.
The ionization constant of HCN is 4.5 × 10–10 at 298 K. Hydrolysis constant of sodium cyanide is
The ionization constant of HCN is 4.5 × 10–10 at 298 K. Hydrolysis constant of sodium cyanide is
The pH of 1 M CH3COONa solution in water will be nearly (pKa for CH3COOH = 4.74)
The pH of 1 M CH3COONa solution in water will be nearly (pKa for CH3COOH = 4.74)
What is the weightage of Equilibrium Class 12 Chemistry in NEET and JEE Main exam?
What is the weightage of Equilibrium Class 12 Chemistry in NEET and JEE Main exam?
In NEET exam, the weightage of Equilibrium is around 3% to 6% and in JEE Main exam, the weightage is 4% to 6.6%.
There are two conditions needed for equilibrium. The net force and net torque acting upon an object must be zero.
There are four types of equilibrium constants: Formation constants, stability constants, association constants, and binding constants.
It consists of concepts such as Le Chatelier's Principle, equilibrium constant, and factors affecting equilibrium. It is not considered an easy chapter.


