Chemistry Chemical Kinetics

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New answer posted

2 months ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

If Rate = K [ N O ] a [ H 2 ] b  

Case I => 7 * 1 0 9 = K ( 8 * 1 0 5 ) a ( 8 * 1 0 5 ) b

Case II =>   2 . 1 * 1 0 8 = k ( 2 4 * 1 0 5 ) a ( 8 * 1 0 5 ) b

Therefore, 7 ? * 1 0 1 2 . 1 = ( 1 3 ) a

or ( 1 3 ) 1 = ( 1 3 ) a a = 1           

Ans. = 1

New answer posted

2 months ago

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A
alok kumar singh

Contributor-Level 10

[ P t C l 4 ] 2 + H 2 O ? [ P t ( H 2 O ) C l 3 ] + C l  

At equilibrium  d x d t = 0 , hence

0 = d [ [ P t C l 4 ] 2 ] d t = 4 . 8 * 1 0 5 [ [ P t C l 4 ] 2 ] 2 . 4 * 1 0 3 [ [ P t ( H 2 O ) C l 3 ] ] [ C l ]           

K c = K f K b = 4 . 8 * 1 0 5 2 . 4 * 1 0 3              

= 2 * 10-2

= 0.02

New answer posted

2 months ago

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A
alok kumar singh

Contributor-Level 10

Heavy water (D2O) is used to study reaction mechanism. O-H bond energy is less than O-D, hence it will produce fast reaction than O-D. Here assertion is true but Reason is false.

New answer posted

2 months ago

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V
Vishal Baghel

Contributor-Level 10

t1/2 = 340 sec      P0 = 55.5 kPa

t1/2 = 170 sec      P0 = 27.8 kPa

? t 1 / 2 ? ( P 0 ) 1 ? n

? 1 ? n = 1 n = 0

? zero order reaction

New answer posted

2 months ago

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A
alok kumar singh

Contributor-Level 10

On decreasing pressure of NO by a factor of '2' the rate of reaction decreases by a factor of '4'

Order of reaction w.r.t 'NO' = 2

New answer posted

2 months ago

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A
alok kumar singh

Contributor-Level 10

According to Arrhenius equation ;

I n k = l n A E a R T                

Here lnk = 33.24  2 . 0 * 1 0 4 T  

E a R = 2 . 0 * 1 0 4      

a n d E a = 2 . 0 * 1 0 4 * R = 2 . 0 * 1 0 4 * 8 . 3 = 1 6 . 6 * 1 0 4 J = 1 6 6 k J      

New answer posted

2 months ago

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A
alok kumar singh

Contributor-Level 10

 Al equilibrium

K f H 2 [ N O ] 2 = K b N 2 H 2 O + H 2

New answer posted

2 months ago

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V
Vishal Baghel

Contributor-Level 10

K = 0 . 6 9 3 t 1 / 2 = 0 . 6 9 3 7 0 * 6 0 = 6 9 3 0 7 * 6 * 1 0 6

= 165 * 10-6 s-1

New answer posted

2 months ago

0 Follower 14 Views

P
Payal Gupta

Contributor-Level 10

On decreasing pressure of NO by a factor of '2' the rate of reaction decreases by a factor of '4'

 Order of reaction w.r.t 'NO' = 2

New answer posted

2 months ago

0 Follower 2 Views

P
Payal Gupta

Contributor-Level 10

For first order reaction,

ln (PP0)=k.t

K=3.465*104

t1/2=0.6933.465*104=2*105 sec

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