Chemistry Chemical Kinetics

Catalyst A reduces the activation energy for a reaction by 10 kJ mol1 at 300K. The ratio of rate constants, $\frac{k_T,Catalysed}{k_T,Uncatalysed}is{e}^x.$ $\frac{{}_{}}{{}_{}}{}^{}$ The value of x is_________. (nearest integer)

[Assume that the pre-exponential factor is same in both the cases. Given R = 8.31 JK1 mol1]

Given below are two statements: one is labelled as Assertion A and the other is labelled as Reason R:
Assertion A: A reaction can have zero activation energy.
Reason R: The minimum extra amount of energy absorbed by reactant molecules so that their energy becomes equal to threshold value, is called activation energy.

In the light of the above statements, choose the correct answer from the options given below:

For a certain reaction, the rate = k[A]²[B]. When the initial concentration of A is tripled keeping concentration of B constant, the initial rate would

The intermediate compound ' X ' in the following chemical reactions is:
Toluene + CrO₂Cl₂ --CS₂--> X --H₃O⁺--> Benzaldehyde

The compound which shows metamerism is :

For a first order reaction A → Products, initial concentration of A is 0.1M, which becomes 0.001 after 5 minutes. Rate constant for the reaction min^-1 is:

The given graph is a representation of kinetics of a reaction.

The y and x axes respectively are for zero and first order reactions, respectively are:

The decomposition of formic acid on gold surface follows first order kinetics. If the rate constant at 300 K is 1.0x10^-3  /s and the activation energy E_a = 11.488 kJ/mol, the rate constant at 200 K is ___________ x10-5  /s. (Round off to the nearest Integer).

[Given R = 8.314 J/molK]

A and B decompose via first order kinetics with half- lives 54.0 min and 18.0 min respectively. Starting from an equimolar non reactive mixture of A and B, the time taken for the concentration of A to become 16 times that of B is __________ min

A reaction has a half life of 1 min. The time required for 99.9% completion of the reaction is ________ min. (Round off to the nearest integer).
[Use In 2 = 0.69; In 10 = 2.3]