Chemistry Chemical Kinetics

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4 months ago

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V
Vishal Baghel

Contributor-Level 10

(4) C? H? O will have different alkyl group attached with polyvalent functional group that's why show metamerism

Only one arrangement possible so can not show metamerism.
(2) C? H? O → CH? – O – CH? – CH? Only one arrangement possible so can not show metamerism.
(1) No polyvalent functional group in C? H? , so can not show metamerism.

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Vishal Baghel

Contributor-Level 10

k = (2.303 / 5) log (0.1 / 0.001) = (2.303 * 2) / 5 = 4.606 / 5 = 0.921 min? ¹

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4 months ago

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V
Vishal Baghel

Contributor-Level 10

For a zero-order reaction Rate Vs conc graph will be straight line parallel to the x-axis.
For a 1st order reaction t? /? vs concentration will again be a straight line parallel to x-axis.

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R
Raj Pandey

Contributor-Level 9

T? = 300 K; K? = 1 * 10? ³ s? ¹
T? = 200 K; K? =?
E_a = 11.488 kJ/mol
Using Arrhenius equation:
log (K? /K? ) = (E_a / 2.303R) * [ (T? - T? ) / (T? )]
log (K? / 10? ³) = (11.488 * 10³ / (2.303 * 8.314) * [ (-100) / (6 * 10? )]
log (K? / 10? ³) = -1
K? / 10? ³ = 10? ¹
K? = 10? s? ¹ or K? = 10 * 10? s? ¹

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4 months ago

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alok kumar singh

Contributor-Level 10

Using the integrated rate laws for both reactions and solving for time 't' yields a value of 108.

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Raj Pandey

Contributor-Level 9

Half life, t? /? = 1min
Let, time of 99.9% completion of reaction be 't' min
Let the reaction is of first order
K = (2.303/t) log? ( [R]? / [R])
[R] = 0.001 [R]?
t = (2.303 * 3 min) / 0.693
t = 9.99 min
the nearest integer is 10.

New answer posted

4 months ago

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R
Raj Pandey

Contributor-Level 9

For the reaction C? H? → C? H? + H? , calculate the enthalpy change (ΔH).

ΔH = [Bond energy (C-C) + 6 * Bond energy (C-H)] - [Bond energy (C=C) + 4 * Bond energy (C-H) + Bond energy (H-H)]

ΔH = 347 + 2 (414) - 611 - 436 = 128 kJ/mol.

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4 months ago

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alok kumar singh

Contributor-Level 10

The change in entropy for the following processes is negative (ΔS = -ve), indicating an increase in order:

Water (l) → Ice (s) at 0°C

H? O (l) → Ice (s) at -10°C

N? (g) + 3H? (g) → 2NH? (g)

Adsorption

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Aadit Singh Uppal

Contributor-Level 10

Unimolecular Reactions might seem to not participate in the collision theory due to the presence of only a single molecule. In such cases, the molecule is activated by external forces such as heat, light, electricity, or by colliding with the walls of the container. This force charges the molecule enough to break the activation barrier and result in an effective collision.

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4 months ago

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alok kumar singh

Contributor-Level 10

Kindly go through the solution

 

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