Chemistry Chemical Kinetics
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New answer posted
a month agoContributor-Level 9
first order reaction
K = (2.303/t) log (a? / (a? - x)
K = (2.303/90) log (a? / 0.25a? ) = 0.0154
t = 60% = (2.303/K) log (a? / a? ) . (2)
= (2.303 / 0.0154) x (1 - 0.602) = 59.51 mins ≈ 60
New answer posted
a month agoContributor-Level 10
SN2 is a bimolecular reaction. This is because as per the rate law,
Rate = k [substrate] [nucleophile]
Here, the rate determining step is dependent on both substrate and nucleophile, unlike SN1 who only involves substrate. Therefore, SN2 is proved to be bimolecular.
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