Chemistry Hydrocarbon

Density ∝ molar mass, as size of given molecules is nearly same

(a) Phenol with Br? / H? O gives 2,4,6-tribromophenol. (High ionisation due to polar solvent and high activation of ring)
(b) Phenol with Br? in CS? /CHCl? /FeBr? gives a mixture of o- and p-bromophenol, with p-bromophenol as the major product. (less ionisation due to non- polar solvent)
[Chemical reactions showing bromination of phenol under different conditions]

Conjugate base is highly stable.
Acidic strength ∝ stability of conjugate base.
So,  cyclopentadiene is most acidic.

Kindly consider the following figure

$C_x{H}_y\left(g\right)+\left(x+\frac{y}{4}\right)O_2\left(g\right)\to xC{O}_2\left(g\right)+\frac{y}{2}{H}_{2}O\left(\mathcal{l}\right)$

V 6V - -

- - 4V

Volume of CO2 = 4 * $V_{C_x{H}_y}$ ${}_{{}_{}{}_{}}$

Vx = 4V

x = 4

Volume of O2 = 6 * $V_{C_x{H}_y}$ ${}_{{}_{}{}_{}}$

$V\left(x+\frac{y}{4}\right)=6V$

$4+\frac{y}{4}=6$

y = 8

Hence

CH₃ – CH₂ – CHO can't be formed.

In case of unsymmetrical alkynes, more positive charge stabilizing carbon attacked by H₂O and finally converted into carbonyl.

Kindly consider the following figure

With CO₂ gas water forms carbonic acid