Chemistry NCERT Exemplar Solutions Class 11th Chapter Ten
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4 months agoContributor-Level 10
This is a short answer type question as classified in NCERT Exemplar
(i) As the size of the cation increases, the thermal stability of carbonate increases. The more stable will be the oxide of an alkaline earth metal, the less stable will be the carbonate. Hence, beryllium carbonate will be highly unstable because its oxide will be stable.
(ii) Alkali metals and alkaline earth metals form oxides with oxygen and give metal oxides. The oxides are basic in nature. BeO is an exception because BeO is amphoteric.
They also react with water to form sparingly soluble hydroxides. On increasing the size of the cations beryllium oxide and magnesiu
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4 months agoContributor-Level 10
This is a short answer type question as classified in NCERT Exemplar
The element from group 2 is beryllium. Be (OH)2 is amphoteric. It reacts with both acids and bases. It reacts with acid to form beryllium chloride and it reacts with base to form beryllate ion which is soluble in sodium hydroxide. The reaction is shown below.
Be (OH)2+2OH−→ [Be (OH)4]2−
Be (OH)2+2HCl→BeCl2+2H2O
Beryllium sulfate are readily soluble in water.
New answer posted
4 months agoContributor-Level 10
This is a short answer type question as classified in NCERT Exemplar
These two elements have similar properties because of their similar atomic and ionic radii.
(i) Both are lighter element and harder than the other metals in their respective groups.
(ii) The halides of both elements, LiCl and MgCl2 are soluble in ethanol.
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4 months agoContributor-Level 10
This is a short answer type question as classified in NCERT Exemplar
(i) O22−+ 2H2O → H2O2+2OH−
(ii) 2O2−+2H2O→2OH−+H2O2+O2
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4 months agoWhen heated in air, the alkali metals form various oxides. Mention the oxides formed by Li, Na and K
Contributor-Level 10
This is a short answer type question as classified in NCERT Exemplar
Alkali metals forms oxide when reacted with air. Lithium forms monoxide, sodium forms peroxide and potassium forms superoxide.
4Li+O2→2Li2O
Na+O2→Na2O2
K+O2→KO2
New answer posted
4 months agoContributor-Level 10
This is a short answer type question as classified in NCERT Exemplar
Lithium has the highest negative reduction potential value. Due to the small size of lithium it has the highest ionization enthalpy. Due to this, the reducing power of lithium is the highest in an aqueous solution.
New answer posted
4 months agoContributor-Level 10
This is a long answer type question as classified in NCERT Exemplar
The element imparts yellow colour to the flame in flame test which means the element of group 1 is sodium. Sodium is used in the transmission of nerve signals and transport of sugars and amino acids into cells. Reactions are shown below.
2Na+O2→Na2O2
4Na+O2→2Na2O
2Na2O+O2→2Na2O2
New answer posted
4 months agoContributor-Level 10
This is a long answer type question as classified in NCERT Exemplar
In group 2, only beryllium is amphoteric in nature which means it reacts with both acids and bases. Also, beryllium only forms covalent oxide due to the covalent nature. So, the element is beryllium.
It reacts with acid to form beryllium chloride and it reacts with base to form beryllate ion which is soluble in sodium hydroxide. The reaction is shown below.
Be (OH)2+2OH− → [Be (OH)4]2−
Be (OH)2+2HCl →BeCl2+2H2O
New answer posted
4 months agoContributor-Level 10
This is a long answer type question as classified in NCERT Exemplar
Beryllium being least reactive does not form hydride by direct heating with dihydrogen. It is prepared by reacting it with lithium aluminum hydride. The reactions are shown below.
8LiH + Al2Cl6→2LiAlH4+6LiCl
2BeCl2+LiAlH4→2BeH2+LiCl+AlCl3
New answer posted
4 months agoContributor-Level 10
This is a long answer type question as classified in NCERT Exemplar
Compound A reacts with water to form compound B. So, the compound A is calcium oxide. When water is added to calcium oxide, calcium hydroxide is formed. It is lime water. The compound gives a milky appearance which is compound C. The compound C is calcium carbonate. On passing, excess carbon dioxide milkiness disappears due to the formation of compound D. The compound is calcium hydrogen carbonate. The reactions are as follows:
CaO+H2O→Ca (OH)2
Ca (OH)2+CO2→CaCO3
Ca (OH)2+CO2+H2O→Ca (HCO3)2
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