Chemistry NCERT Exemplar Solutions Class 12th Chapter Eight

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2 months ago

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A
alok kumar singh

Contributor-Level 10

2PbNO32? Δ2PbO+2NO2+O2

2NO2? N2O4 colourless

N2O4+2NO? 2N2O3

Oxidation state in N2O3 is +3

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Payal Gupta

Contributor-Level 10

Valence shell electronic configuration of Eu in +2 O.S is,

E u 2 + = 6 s 0 4 f 7                

It has half filled f-sub shell and stable.

New answer posted

3 months ago

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V
Vishal Baghel

Contributor-Level 10

Following is the reaction of KMnO4 in basic medium with thiosulphate anion.

8MnO4+7+3S2O3+H2O8MnO2|+4+6SO4+2OH

Change = 7 – 4 = 3

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Vishal Baghel

Contributor-Level 10

  S c 3 + 3 d 0 electron in last subshell

Zn2+3d10 electron in last subshell

Ti4+3d0 electron in last subshell

Cu2+3d9 electron in last subshell

V2+3d3 electron in last subshell

Ti3+3d1 electron in last subshell

Mn2+3d5 electron in last subshell

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3 months ago

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alok kumar singh

Contributor-Level 10

Sol. first order reaction

K=2.303tlog? a0a0-x

K=2.30390log? a00.25a0

=0.0154

t=60%=2.303Klog? a0a0. (2)=2.3030.0154* (1-0.602)=59.51mins60

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alok kumar singh

Contributor-Level 10

Sol. (i) Foam - Froth (e)

(ii) Gel - Jellies (c)
(iii) Aerosol - smoke (a)
(iv) Emulsion - milk (f)

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3 months ago

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P
Payal Gupta

Contributor-Level 10

Consider the image below

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Payal Gupta

Contributor-Level 10

Lindlar's catalyst reduces alkynes to cis-alkene.

Lindlar's catalyst reduces alkynes to cis-alkene.

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Payal Gupta

Contributor-Level 10

Aromatic species are most stable, here

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Payal Gupta

Contributor-Level 10

For ideal gas using ;

PM = dRT

P = ( R T M ) d

Comparing with y = mx + C

Slope, m =  R T M

Slope  T

So; higher the slope higher the T

Hence, T3 > T2 > T1

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