Chemistry
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New answer posted
9 months agoContributor-Level 10
This is a short answer type question as classified in NCERT Exemplar
Water and alcohol are polar molecules which have high electronegative O atm so they have hydrogen bonding along with dipole-dipole interaction. Hexane is a nonpolar molecule that has London dispersion force which is a weak force between the molecules. Water has stronger H-bonding than alcohol. So, the order of attractive force will be:
Hexane < Alcohol < Water
More attractive forces between the molecules, the greater the magnitude of surface tension of the liquid.
New answer posted
9 months agoContributor-Level 10
This is a short answer type question as classified in NCERT Exemplar
The assumption of the kinetic theory of gases which states that- “ there is no force of attraction between the molecules of a gas. ” is a correct statement. Ideal gas has minimum force of attraction between the molecules and hence, it cannot be liquified. Liquefaction of a gas can only be done when the force of attraction between the molecules increases, which is not possible for an ideal gas.
New answer posted
9 months agoContributor-Level 10
This is a short answer type question as classified in NCERT Exemplar
Unit of R depends on the units of p, V and T are measured, We know, R=
New answer posted
9 months agoContributor-Level 10
This is a short answer type question as classified in NCERT Exemplar
On increasing the pressure slightly the gas 'A' liquefies but gas B does not liquify even on applying high pressure until it is cooled at same conditions of temperature and pressure filled in equal capacity containers it happens because the gas 'A' being at the critical temperature liquifies on slightly increasing the pressure and gas 'B' being at higher temperature than critical temperature does not liquifies even on applying high pressure until it is cooled.
New answer posted
9 months agoContributor-Level 10
This is a short answer type question as classified in NCERT Exemplar
A gas that follows Boyle's law, Charle's law and Avogadro's law is called an ideal gas.
Real gas behaves ideal under low pressure and high temperature. Under these conditions, the intermolecular interactions are minimum.
New answer posted
9 months agoContributor-Level 10
This is a short answer type question as classified in NCERT Exemplar
The molar volume of both nitrogen and argon at 273.15 K and 1 atm is 22.4 L.
At STP (1 atm pressure and 273.15 K or 00 C), the molar volume i.e the volume of 1 mole gas is 22.4L.
New answer posted
9 months agoContributor-Level 10
This is a short answer type question as classified in NCERT Exemplar
(a) HCl, HBr and HI have dipole-dipole and london dispersion interaction whereas HF has hydrogen bonding in addition (due to the high electronegativity of the F atom).
(b) The electronegativity decreases from Cl, Br and I so the dipole-dipole interaction will also decrease as HCl > HBr > HI and it is contrary to the boiling point order which is HCl < HBr < HI. This confirms that the London interaction is predominant.
(c) F atom has the highest electronegativity so it has hydrogen bonding interaction in addition to dipole-dipole and london dispersion interaction which leads to the highest boiling poi
New answer posted
9 months agoContributor-Level 10
This is a short answer type question as classified in NCERT Exemplar
The factors that determine the states of matter are:
1. Temperature
2. Pressure
3. Mass and volume
New answer posted
9 months agoContributor-Level 10
This is a short answer type question as classified in NCERT Exemplar
Physical state of ice, water and steam are very different but the chemical composition of water in all the three states is H2O.
New answer posted
9 months agoContributor-Level 10
This is a short answer type question as classified in NCERT Exemplar
(a) the greatest volume is occupied by CH4 and
(b) the smallest volume by NO
According to Avagadro's Law,
Volume of 1 mole of a gas at STP = 22.4 L
Now, we know,
1 mole = Molar mass
∴ Volume of 28g mol-1 of CO at STP = 22.4 L
So, Volume of 1 g of CO at STP = 22.4 L / 28 g mol-1
Similarly,
Volume of 1 g of H2O at STP = 22.4 L / 18 g mol-1
Volume of 1 g of CH4 at STP = 22.4 L / 16 g mol-1 (
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