Chemistry

$5C_2{O}_4^{2-}+2Mn{O}_4^{-}+16H^{+}\to 2M{n}^{+}+8H_{2}O+10C{O}_2$

5 moles of $C_2{O}_4^{2-}$ ${}_{}{}_{}^{}$ is needed to reduce 2 moles of $Mn{O}_4^{2-}$ ${}_{}^{}$

1 mole of $C_2{O}_4^{2-}$  is needed to reduce $\frac{2}{5}$  moles of $Mn{O}_4^{2-}$

Sn = [Kr]4d105s25p2

Sn (Z = 50) belongs to p-block element.

H2SO5

: x + 2 (+1) + 3 (–2) + 2 (–1) = 0

x = + 6.

CH₃COONa is salt of weak acid with strong base

$\therefore pH=7+\frac{1}{2}p{K}_a+\frac{1}{2}logC$

$pH=7+\frac{1}{2}*4.74+\frac{1}{2}*log1$

$pH=9.37\approx 9.4$

On increasing pressure, equilibrium moves in that direction where number of gaseous moles decreases.

Kindly go through the solution

K_h = Kw/Ka = 2.22 x 10^-5

Total kinetic energy associated with 'n' moles of monoatomic gas is =   $\frac{3}{2}nRT$

In physisorption multimolecular layers are formed on solid surface.