Chemistry

Electrophoresis : The migration of colloidal particles under the influence of an electric field is known as electrophoresis.

Kindly go through the answers

$r_1=k{\left[x\right]}^n$ … (i)

$$ $2r_1=k{\left[4x\right]}^n$  … (ii)

$\left(ii\right)÷\left(i\right)$

$\Rightarrow \frac{2r_1}{r_1}=\frac{k{\left[4x\right]}^n}{k{\left[x\right]}^n}$

$\Rightarrow 2={\left(2\right)}^{2n}$

$\Rightarrow n=\frac{1}{2}$

XeF2 : Hybrid orbital = sigma bond + L.P

= 2 + 3

= 5 = sp3d

Shape will be linear

For a first order reaction.

$k=\frac{0.693}{t_{\raisebox{1ex}{$1$}\!\left/ \!\raisebox{-1ex}{$2$}\right.}}=\frac{0.693}{231}=3*10^{-3}{s}^{-1}$   

Z=109 : Unnilennium = Meitnerium

$5C_2{O}_4^{2-}+2Mn{O}_4^{-}+16H^{+}\to 2M{n}^{+}+8H_{2}O+10C{O}_2$

5 moles of $C_2{O}_4^{2-}$ ${}_{}{}_{}^{}$ is needed to reduce 2 moles of $Mn{O}_4^{2-}$ ${}_{}^{}$

1 mole of $C_2{O}_4^{2-}$  is needed to reduce $\frac{2}{5}$  moles of $Mn{O}_4^{2-}$

Sn = [Kr]4d105s25p2

Sn (Z = 50) belongs to p-block element.

H2SO5

: x + 2 (+1) + 3 (–2) + 2 (–1) = 0

x = + 6.

CH₃COONa is salt of weak acid with strong base

$\therefore pH=7+\frac{1}{2}p{K}_a+\frac{1}{2}logC$

$pH=7+\frac{1}{2}*4.74+\frac{1}{2}*log1$

$pH=9.37\approx 9.4$