Chemistry

Which will have the highest enol content?

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Contributor-Level 10

Aromaticity drives the highest enolic percentage of given structure:

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Chemistry Class 11th

Given below are two statements. One is labelled as Assertion A and the other is labelled as Reason R.

Assertion (A) : The first ionization enthalpy for oxygen is lower than that of nitrogen

Reason (R) : The four electrons in 2p orbitals of oxygen experience more electron electorn repulsion.

In the light of the above statements, choose the correct answer from the options given below:

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Contributor-Level 10

1^st ionization energy of N>O in oxygen atom, 2 electrons out of 4 electron of 2p orbital resulting in an increased electron repulsion.

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Kindly consider the following

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This is the nucleophilic addition reaction of Grignard reagent on carbonyl compounds

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A 42.12% (w/v) solution of NaCl causes precipitation of a certain sol in 10 hours. The coagulating value of NaCl for the sol is

[Given molar mass : Na = 23.0g mol^-1; Cl = 35.5g mol^-1]

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Data is not sufficient but official answer is (D)

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Chemistry Equilibrium

4.0 moles of argon and 5.0 moles of PCl₅ are introduced into an evacuated flask of 100 litre capacity at 610 K. The system is allowed to equilibrate. At equilibrium, the total pressure of mixture was found to be 6.0 atm. The K_p for the reaction is

[Given R = 0.082 L atm K^-1 mol^-1]

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Contributor-Level 10

Moles of PCl₅ = 5 mol

Moles of Ar = 4 mol

Total no of moles = 9 moles

$P_{T o t a l} = \frac{n R T}{V} = \frac{9 * 0.0821 * 610}{100} = 4.5 a t m$

$P_{P C l_{5}} = X_{P C l_{5}} * P_{T} = \frac{5}{9} * 4.5 = 2.5 a t m$

$P_{A r} = X_{A r} * P_{T} = \frac{4}{9} * 4.5 = 2 a t m$

$P C l_{5} \overset{}{?} P C l_{3} + C l_{2}$

2.5 0 0

2.5 - P P P

$P_{T o t a l} = 2.5 - P + P + P + P_{A r} = 6$

P = 1.5

...more

Moles of PCl₅ = 5 mol

Moles of Ar = 4 mol

Total no of moles = 9 moles

$P_{T o t a l} = \frac{n R T}{V} = \frac{9 * 0.0821 * 610}{100} = 4.5 a t m$

$P_{P C l_{5}} = X_{P C l_{5}} * P_{T} = \frac{5}{9} * 4.5 = 2.5 a t m$

$P_{A r} = X_{A r} * P_{T} = \frac{4}{9} * 4.5 = 2 a t m$

$P C l_{5} \overset{}{?} P C l_{3} + C l_{2}$

2.5 0 0

2.5 - P P P

$P_{T o t a l} = 2.5 - P + P + P + P_{A r} = 6$

P = 1.5 atm

$K_{P} = \frac{1.5 * 1.5}{1} = 2.25$

less

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${(C_{7} H_{5} O_{2})}_{2} \overset{h v}{\to} [X] \to 2 {\overset{•}{C}}_{6} H_{5} + 2 C O_{2}$

Consider the above reaction and identify the intermediate 'X'

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Chemistry Chemistry Chemical Bonding and Molecular Structure

Contributor-Level 10

This is the formation of free radical mechanism, hence free radical will be formed

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Consider the species CH₄, $N H_{4}^{+} a n d B H_{4}^{-} .$ Choose the correct option with respect to the there species

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Chemistry Chemistry Organic Chemistry

Given below are two statements:

Statement I: In 'Lassaigne's Test', when both nitrogen and sulphur are present in an organic compound, sodium thiocyanate is formed.

Statement II: If both nitrogen and sulphur are present in an organic compound, then the excess of sodium used in sodium fusion will decompose the sodium thiocyanate formed to given NaCN and Na₂S.

In the light of the above statements, choose the most appropriate answer from the option given below:

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Contributor-Level 10

Regarding Lassaigne's Test, both statement are correct.

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Chemistry Structure of Atom

Which of the following is the correct plot for the probability density $ψ^{2} (r)$ as a function of distance 'r' of the electron from the nucleus for 2s orbital?

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Contributor-Level 10

For 2S, number of radial moles = $n - l - 1 = 2 - 0 - 1 = 1$ and $Ψ^{2} (r)$ will always be positive

$∴ o p t i o n (B) i s c o r r e c t ?$ it has one radial node and it is positive.

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Chemistry Class 11th

Polar stratospheric clouds facilitate the formation of:

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