Chemistry

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New answer posted

9 months ago

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A
alok kumar singh

Contributor-Level 10

S ( g ) + 6 F ( g ) S F 6 ( g )  

Δ H 0 R = Δ H 0 f ( S F 6 ) Δ H 0 f ( S ) 6 * Δ H 0 f ( F )            

= (-1100) - (275) -6 (80) = -1855

Δ H 0 S F = 1 8 5 5 6 = 3 0 9 . 1 6 K J / m o l 3 0 9            

New answer posted

9 months ago

0 Follower 1 View

A
alok kumar singh

Contributor-Level 10

Seliwanoff's test is used to distinguish carbohydrates while xanthoproteic test is used to distinguish proteins

New answer posted

9 months ago

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A
alok kumar singh

Contributor-Level 10

Oxide    Nature

CaO                     Basic

B2O3                     Acidic

SiO2                     Acidic

BaO                     Basic

N2O               

...more

New answer posted

9 months ago

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A
alok kumar singh

Contributor-Level 10

Species               B.O

Ne2                        0

N2                           3

F2                 1

O2                          2

 

New answer posted

9 months ago

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A
alok kumar singh

Contributor-Level 10

Kindly go through the solution

 

New answer posted

9 months ago

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A
alok kumar singh

Contributor-Level 10

2, 4-DNP (Brady's Reagent) is used to test carbonyl compound

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9 months ago

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A
alok kumar singh

Contributor-Level 10

(a) Na2CO3 -> Solvay

(b) Ti -> Van-Arkel

(c) Cl2 -> Deacon

(d) NaOH -> Castner – kellner

New answer posted

9 months ago

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A
alok kumar singh

Contributor-Level 10

 

It is an intramolecular aldol condensation

 

New answer posted

9 months ago

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A
alok kumar singh

Contributor-Level 10

A > B > C > D

Lone pair is localized in (A) while all 3 have delocalized lone pair but they can be compared by 3° > 2° > 1° because methyl group increases the basicity.

New answer posted

9 months ago

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A
alok kumar singh

Contributor-Level 10

Kindly go through the solution

S > Se > Te > O

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