Circular Motion

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New answer posted

2 weeks ago

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R
Raj Pandey

Contributor-Level 9

Let is the angle made by the wire with the vertical.

Here,  .

 

 

 

New answer posted

2 months ago

0 Follower 1 View

S
Syed Aquib Ur Rahman

Contributor-Level 10

From the physics perspective, in uniform circular motion, speed and angular velocity are constant. That makes the angular acceleration and tangential acceleration are zero. Non-uniform motion, on the other hand, has varying speed and angular velocity, where angular acceleration is non-zero. 

New answer posted

2 months ago

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S
Syed Aquib Ur Rahman

Contributor-Level 10

The period T is the time taken to complete one full revolution (2? radians). In uniform circular motion, it relates to angular velocity by? =2? /T and to tangential speed by v=? r=2? r/T .

New answer posted

2 months ago

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S
Syed Aquib Ur Rahman

Contributor-Level 10

The principle of circular motion follows Newtonian mechanics. It can be stated that an object will move in a circle only when there is a centripetal force that continuously acts perpendicular to its tangential velocity. That changes the direction but not its speed. The inward acceleration a_c = v squared/r obeys Newton's laws and ensures circular path motion. 

New answer posted

2 months ago

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S
Syed Aquib Ur Rahman

Contributor-Level 10

Circular motion has the following characteristics.

  • Fixed radius with the same and constant distance from the centre
  • Constant speed, when the motion is uniform
  • A changing velocity vector with continuous direction of change
  • Centripetal acceleration that is directed radially inwards, while the force that causes it is the centripetal force that maintains the curved path

New answer posted

2 months ago

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V
Vishal Baghel

Contributor-Level 10

By N L M : T sin θ =   m ω 2 R - (1)

& R = l sin θ - (2)

From (1) & (2)

T s i n θ = m ω 2 l s i n θ

T = m ω 2 l

8 0 = ( 1 0 0 1 0 0 0 ) ω 2 * 2

8 0 0 2 = ω 2

ω 2 = 4 0 0

ω = 2 0 r a d / s e c

And, ω = 2 π N 2 π

N = 2 0 * 6 0 2 π

N = 6 0 0 π r p m = k π

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